How do I extract data from XML columns into their own columns?

I have 280,000 rows that contain a column called body. This column has xml data.

A copy of one column value is shown below. I need to extract into new columns the data contained in the elements of the XML field esn, timestamp_utc, Latitude, Longitude, 开发者_JAVA百科and triggers, with the column names being the same as the element names.

I have worked on this in the past, but gave up on it. I am not at a point I need to figure out how to do it. Please give me any suggestions you may have.

Thank you!!!

<?xml version="1.0" encoding="UTF-8"?>
<telemetry>
   <esn>1127877</esn>
   <timestamp_utc>5/28/2011 9:18:30 PM</timestamp_utc>
   <latitude>59.023672</latitude>
   <longitude>-118.836408</longitude>
   <ignition>N</ignition>
   <geofence>0</geofence>
   <speed>0</speed>
   <heading>0</heading>
   <milestraveled>0.00</milestraveled>
   <triggers>Contact_State_Change, IO_1_Closed, No_Vibration_Detected, </triggers>
   <miscellaneous>Standard3</miscellaneous>
   <contact1counts>0</contact1counts>
   <contact2counts>0</contact2counts>
   <io1state>0</io1state>
   <io2state>0</io2state>
</telemetry>

You can use something like this:

SELECT  
   ID,
   body.value('(telemetry/esn)[1]', 'bigint') AS 'esn',
   body.value('(telemetry/timestamp_utc)[1]', 'varchar(50)') AS 'esn',
   body.value('(telemetry/longitude)[1]', 'float') AS 'longitude',
   body.value('(telemetry/latitude)[1]', 'float') AS 'latitude',             
   body.value('(telemetry/timestamp_utc)[1]', 'varchar(50)') AS 'triggers'
FROM
   dbo.YourTableNameHere

Does that work, and give you the right data??