PHP variables inside a variable [closed]

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I have an error somewhere in this line of code, if I take "by" off the line it works fine.

$msg = 'An Order has just been submitted on CID, Number' . $_POST['orderNumber']'by' .$name;

Can any开发者_JS百科one spot my mistake?

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I would advise you to utilize one of PHPs core language features. PHP supports variable interpolation in double quoted strings. That's much simpler than the cumbersome string concatenation:

$msg = "An Order has just been submitted on CID, Number $_POST[orderNumber] by $name";

Note that as special exception no array key quotes are to be used there for simple arrays. (Other examples see the manual http://php.net/manual/en/book.strings.php)

Also note that you should actually escape (see htmlspecialchars) incoming $_POST or $_GET variables, if they are to be used for output again.

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Yes, you never concatenate $_POST['orderNumber'] and 'by' properly (via the . operator).

$msg = 'An Order has just been submitted on CID, Number ' . $_POST['orderNumber'] . ' by ' . $name; // Notice the . (and a few spaces)

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you forgot to concatenate 'by'. Just add the concatenation . infront of 'by'

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You for got the .

$_POST['orderNumber'] . 'by' 

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Try this

$msg = 'An Order has just been submitted on CID, Number'.$_POST['orderNumber'].'by'.$name;