How to get all unchecked radio buttons

Ok, so 开发者_如何学运维I've got a jQuery code which constructs my radio inputs from XML data, like this:

var items = xml.children('item');
if (items.length > 0)
{
    var ul = $('<ul/>',{
        class: 'priceList'
    });
    items.each(function(){
        var $this = $(this);
        var li = $('<li/>');
        var img = $('<img/>',{
            src: 'products/' + $this.children('image').text(),
        });
        var input = $('<input/>',{
            type: 'radio',
            id: $this.children('id').text(),
            name: 'products'
        });
        var span = $('<span/>',{
            text: $this.children('price').text() + ' USD'
        });
        var label = $('<label/>',{
            for: $this.children('id').text()
        });
        label.append(img);
        label.append("</br>");
        label.append(span);
        li.append(input);
        li.append(label);
        ul.hide().append(li).fadeIn('slow');
    });
    return ul;
}
return null;

Now I need a nice way to find all unchecked radio labels and do something with them, e.g. fade them out or change a css property. Since the XML list consists of nearly 40 items, writing an if-else construction is a no-go. Need a good solution. Thanks in advance!

EDIT: See my answer below.

Found it myself. None of the above answers worked for me, which is strange, because most of them should be totally legit.

What I found to be working is actually

$('input[type="radio"]:not(:checked)')

And in my case I needed

$('li input[type="radio"]:not(:checked) + label')

And the whole code is:

//we'll need m for detecting a click outside of element with our radio buttons...
var m = false;
$(document).ready(function(){
    $.ajax({
        type: "GET", url: 'xml.xml', dataType: 'xml',
        success: function(data){
            var xml = $(data);
            $('#windowList').append( ItemToUl(xml.children()) );
        }
    });
    $('.calc').hover(function(){ 
        m=true; 
    }, function(){ 
        m=false; 
    });
    $("body").mousedown(function(){ 
        if(! m) { 
            //...and unchecking a checked radio. I heard that .attr() was deprecated but couldn't get .prop() to work
            $('li input[type="radio"]:checked').attr('checked', false);
            $('li input[type="radio"]:not(:checked) + label').fadeTo('slow', 1);
        }
    });
    $("li input").live("change", function(){
        $('li input[type="radio"]:checked + label').fadeTo('slow', 1);
        $('li input[type="radio"]:not(:checked) + label').fadeTo('slow', 0.45);
    }); 
});

//constructing function, etc...

Try this (also see my jsfiddle):

$('input').not(':checked')

i think this sould work

$("input:!checked");

You may want to put a class selector in there as well.

Then do an .each to do something with the elements

$('form input[type="radio"]').not(':checked').each(function() {
    $(this).addClass('unchecked');
    // or
    $(this).slideUp('slow');
});

Obviously the element you use is up to you but the :unchecked selector is what you're after.