split version using Regexp

I have a version like this “5.3.08.01”, I want to split this version string into four so that each digit get assigned to variables, means it should be like this:

A= 5

B=3

C=08

D=01

I tried doing like this pattern="(\d*).(\d*).(\d*).(\d*)"

above expression gives me first digit “5”, now how to get 开发者_C百科rest of the digits? Can anyone help me out on this I will be thankful to you

You need to escape the dot (.), and I'd use a + instead of * to make it at least one digit:

(\d+)\.(\d+)\.(\d+)\.(\d+)

language is not specified so I can suggest java solution (and I'm pretty sure that c# has similar one):

String ip = "“5.3.08.01";
String[] nums = ip.split ("."); //array of 4 elements