How to return html instead of strings in php dom parser
<?php
$convert = function($src) {
return '<div>'.$src.'</div>';
};
$doc = new DOMDocument;
$doc->loadhtml(getHTML());
foo($doc, $convert);
echo "after: ", $doc->savehtml(), "\n\n";
function foo(DOMDocument $doc, $fn) {
$xpath = new DOMXPath($doc);
$imgs = array();
foreach( $xpath->query('/html/body//img') as $n ) {
$imgs[] = $n;
}
foreach($imgs as $n) {
$txt = $fn($n->getAttribute('src'));
$div = $doc->createElement('div', $txt);
$n->parentNode->replaceChild($div, $n);
}
}
function getHTML() {
return '<html><head><title>...</title></head><body>
<p>lorem ipsum <img src="a.jpg" alt="img#1"/></p>
<p>dolor sit amet<img src="b.jpg" alt="img#2"/></p&g开发者_JAVA百科t;
<div><div><div><img src="c.jpg" alt="img#3" /></div></div></div>
</body></html>';
}
In the above code in the third line doesn't appear as html in the output, it show as the string. How to return a html tag in this program.
Use echo() not return() when printing the HTML
This should do it:
<?php
$doc = new DOMDocument;
$doc->loadhtml(getHTML());
replaceImageTags($doc);
echo "after: ", $doc->savehtml(), "\n\n";
function replaceImageTags(DOMDocument $doc)
{
$xpath = new DOMXPath($doc);
$imgs = array();
foreach($xpath->query('/html/body//img') as $n ) {
$imgs[] = $n;
}
foreach($imgs as $n)
{
$div = $doc->createElement('div', $n->getAttribute('src'));
$n->parentNode->replaceChild($div, $n);
}
}
function getHTML() {
return '<html><head><title>...</title></head><body>
<p>lorem ipsum <img src="a.jpg" alt="img#1"/></p>
<p>dolor sit amet<img src="b.jpg" alt="img#2"/></p>
<div><div><div><img src="c.jpg" alt="img#3" /></div></div></div>
</body></html>';
}
Outputs:
after: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd"> <html><head><title>...</title></head><body>
<p>lorem ipsum <div>a.jpg</div></p>
<p>dolor sit amet<div>b.jpg</div></p>
<div><div><div><div>c.jpg</div></div></div></div>
</body></html>
加载中,请稍侯......
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