Identifying a String within a file such that it starts and ends with a quote

i am writing a scheme interpreter in Java. Files contain m开发者_运维问答any lines/words This is one of the lines in the file:

"xx'x v \"yyyyy\"... eee dddd ffff\\\n"

I have to identify it such that the whole string is returned, but in my program, it only reads "xx'x v \" and then reads the other words from " to \" Any help is highly appreciated

String text = "";
    int nextString = t;         

    while(!isString(nextString)){           

            nextString = reader.read();
            int next = peek();              

            if (nextString == '\\' && next =='"'){
                nextString = reader.read();                                                     

                if(Character.isSpaceChar(next)){
                    text+=" ";
                }                   
            }               
            text += (char) nextString;
    }       
    return new StringToken(text, lineNumber);

}

if you don't want to use regular expression maybe you can use:

String text = "";
    int nextString = t;         

    while(!isString(nextString)){           

            nextString = reader.read();
            int next = peek();              

            if (nextString == '\\' && next =='"'){
                nextString = reader.read(); 
                text += (char) nextString;
               nextString = reader.read();            
            }     
           if(Character.isSpaceChar(next)){
                    text+=" ";
                }           
            text += (char) nextString;
    }       
    return new StringToken(text, lineNumber);
}

Using regular expressions, for example:

[^\\]\"(.*[^\\])\"

This will only work if the first " is not the first character of the string. The string you want is the one enclosed between (). For example, if I pass \"garbage"Hello\"foo", it will get Hello\"foo (this is what you want if I understood right).

I actually don't know how regex's Java classes handle () in regexs.