jQuery form not being submitted. Firebug no errors

This jQuery isn't working. When i click Vote nothing happens. The div ratecontainer should disappear and nothing is inserted into MySQL when i check. In Firebug i get no errors. What did i do wrong?

echo "<div class='ratecontainer'>   
<form id='rateform' action=''>  
<input type='hidden' id='rateid' value='$stackid' />
<input type='hidden' id='type' value='1' />     
<a cl开发者_如何学Pythonass='vote'>Vote</a>
</form>
</div>";

 $(function() {
$('.vote').click(function() {


    var rate= $("#rateid").val();  
    var type= $("#type").val(); 
    var vote = "0";    
    var dataString = 'id=' + rate + '&type=' + type + '&v=' + vote;

      //alert (dataString);return false;
      $.ajax({
        type: "POST",
        url: "/rate.php",
        data: dataString,
        success: function() {

          $('.ratecontainer').hide();

         }
      });
      return false;

});

});

I'm assuming that your jquery code is inside

 <script type="text/javascript">
 </script>

?

I don't see it right away. But I know there is a really nice jQuery plugin to make this easier for you: http://jquery.malsup.com/form/

You should have rate.php do some debugging... for example print_r($_POST);

Your code should probably be like this:

<div class='ratecontainer'>   
    <form id='rateform' action=''>  
        <input type='hidden' id='rateid' value='<?php echo $stackid ?>' />
        <input type='hidden' id='type' value='1' />     
        <a class='vote'>Vote</a>
    </form>
</div>

<script>
$(function() {
  $('.vote').click(function() {


    var rate= $("#rateid").val();  
    var type= $("#type").val(); 
    var vote = "0";    
    var dataString = 'id=' + rate + '&type=' + type + '&v=' + vote;

     //alert (dataString);return false;
     $.ajax({
       type: "POST",
       url: "/rate.php",
       data: dataString,
       success: function() {

         $('.ratecontainer').hide();

        }
      });
      return false;

  });

});
</script>

And don't have that wrapped in a big <?php ?> tag. Assuming your rate.php is written correctly (which is a stretch) this should work. (jsFiddle)