How do you print the day name given a day number in SQL Server 2005 using SQL commands?
I want to be able to pass in a day number like 1, 2, 3 o开发者_JAVA百科r 7 and it will return the day name like Sunday, Monday, Tuesday or Saturday. I know there is the option of using a case
statement but I would like to do this using SQL commands, would this be at all possible?
DECLARE @m VARCHAR
SET @m=1
SELECT CASE WHEN @m=1 THEN 'Sunday' END
I have already commented on this question when looking for an answer but user @harper suggested that I should submit a new question with a full description.
EDIT: there is currently answers are given for case statement mostly except one . so again now i am putting my question again here is
" I would like to do this using SQL commands, would this be at all possible?"
Try this :
declare @m varchar
set @m=1
SELECT DATENAME(DW,CAST(@m AS INT))
SQL Server Denali has the CHOOSE
function that will make this more concise. In the meantime just use CASE
inside the UDF.
CREATE FUNCTION dbo.WeekDay(@d int)
RETURNS VARCHAR(9)
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS
BEGIN
RETURN
(
SELECT
CASE @d
WHEN 1 THEN 'Sunday'
WHEN 2 THEN 'Monday'
WHEN 3 THEN 'Tuesday'
WHEN 4 THEN 'Wednesday'
WHEN 5 THEN 'Thursday'
WHEN 6 THEN 'Friday'
WHEN 7 THEN 'Saturday'
END
)
END
CREATE FUNCTION dbo.udf_DayOfWeek(@dtDate DATETIME)
RETURNS VARCHAR(10)
AS
BEGIN
DECLARE @rtDayofWeek VARCHAR(10)
SELECT @rtDayofWeek = CASE DATEPART(weekday,@dtDate)
WHEN 1 THEN 'Sunday'
WHEN 2 THEN 'Monday'
WHEN 3 THEN 'Tuesday'
WHEN 4 THEN 'Wednesday'
WHEN 5 THEN 'Thursday'
WHEN 6 THEN 'Friday'
WHEN 7 THEN 'Saturday'
END
RETURN (@rtDayofWeek)
END
GO
-- Call this function like this:
SELECT dbo.udf_DayOfWeek(GETDATE()) AS DayOfWeek
orignally from : SQL SERVER – UDF – Get the Day of the Week Function
SELECT DATENAME(DW,CAST(a AS INT))
Here we can change the value of a as 0 to 6
Default, 0-Monday to 6- Sunday.
If we use a=7 then it will be calculated as 0, because 7-7=0.
精彩评论