why this java regex is not working as I want?

These are two type of string I can get in input:

String mex1 = "/ABCD/YY YYYYY SPA QWE XXXXX XXXXX SPA - 开发者_运维百科02342990153*XXXXX XXXX SPA ABCD LEGALI";
String mex2 = "/ABCD/YY YYYYY SPA QWE XXXXX XXXXX SPA - 02342990153*XXXXX XXXX SPA ABCD LEGALI/ORDERS/9865432342990160";

Which fall in two possible cases, with */some_word/some_number* and without it

I have written this regex which is giving a result I don't understand:

String mex=//<one of two input cases as already explained>
Pattern p = Pattern.compile("(/ABCD/)(.+ )(/\\w+/\\d+)?");
Matcher m = p.matcher(mex);
if(m.find()) {      
  System.out.println(m.group(1)); 
  System.out.println(m.group(2)); // this the group I would like to retrieve...
}

And the result is:

mex2

/ABCD/
YY YYYYY SPA QWE XXXXX XXXXX SPA - 02342990153*XXXXX XXXX SPA ABCD LEGALI

mex1
/ABCD/
YY YYYYY SPA QWE XXXXX XXXXX SPA - 02342990153*XXXXX XXXX SPA ABCD

which is not what I expected in particular with mex2, where the string I want to retrieve get truncated. Also, why after including the boundaries results in match find = false ?

Pattern p = Pattern.compile("^(/ABCD/)(.+ )(/\\w+/\\d+)?$");

thanks

There are two issues with your regex:

1. The (.+ ) requires a space at the end of the group.
2. The .+ is a greedy match so it matches the remainder of the string.

Try the following regex:

/ABCD/(.+?)(/\\w+/\\d+)?$

Try this one

(/ABCD/)([^\/]+(/\\w+/\\d+)?)

The [^\/] will capture anything but /