开发者

Why is this php array not getting anything?

I'm trying to submit a 'defacto' option array (although it looks like a search bar) to a php file and show the results that I sent. This is what it looks like now:

Why is this php array not getting anything?

Link to image: http://i.imgur.com/Ak4dk.png

And so what I did was that I changed the submit.php from this:

<?php print_r($_REQUEST); ?>

To this:

<?php

if(isset($_POST['$_REQUEST']))
{
  $aVenues = $_POST['select3'];

  if(!isset($aVenues))
  {
    echo("<p>You didn't select any venues!</p>\n");
  }
  else
  {
    $nVenues = count($aVenues);

    echo("<p>You selected $nVenues venues: ");
    for($i=0; $i < $nVenues; $i++)
    {
      echo($aVenues[$i] . " ");
    }
    echo("</p>");
  }
}

?>

Here's a link to the page, and as you can see the submit.php shows an empty page, why is this :/ ? 开发者_如何学PythonThank youu :)


Try

if(isset($_POST['select3'])) 

Not what you have at the moment. That index won't exist in $_POST.


the if

if(isset($_POST['$_REQUEST']))

fails.

$_REQUEST and $_POST are both different arrays, 1 containing only POST data, the other combining POST and GET.

The check should be (I assume)

if ($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($_POST)) { }

To verify that data actually has been posted to the server.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜