Switch between JSON (Jackson processor) and XML (XStream) or can i use it simultaneously?

I'm trying to build an Web-Server which can serialize an Objec开发者_开发技巧t into JSON and XML. Since I've integrated Jackson (using an example-Project) I'm able to access an JSON-Serialized Object via my REST Interface, but i'd like to get XML too.

this...

@Controller
@RequestMapping("/main/ajax")
public class AjaxController {

@RequestMapping(value = "/blah", method = RequestMethod.GET, headers = "Accept=application/xml")
public @ResponseBody List<String> blah(@RequestParam(value="input") String input){

            List<String> stringList = new LinkedList<String>();
            stringList.add("i");
            stringList.add("am");
            stringList.add("an");
            stringList.add("json object");
            stringList.add(input);

            return stringList;
    }
 }

whit this query:

http://localhost:8080/spring-json/krams/main/ajax/blah?input=foobar

produces that output:

["i","am","an","json object","foobar"]

Any hints?

UPDATE #1: I implemented the ContentNegotiatingViewResolver...

<bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
  <property name="order" value="1" />

  <property name="mediaTypes">
    <map>
      <entry key="json" value="application/json" />
      <entry key="xml" value="application/xml" />
    </map>
  </property>

  <property name="defaultViews">
    <list>

      <!-- JSON View -->
      <bean class="org.springframework.web.servlet.view.json.MappingJacksonJsonView" />

      <!-- XML View --> 
      <bean class="org.springframework.web.servlet.view.xml.MarshallingView">
         <constructor-arg>
          <bean class="org.springframework.oxm.xstream.XStreamMarshaller" />
        </constructor-arg>
      </bean>  

    </list>
  </property>

  <property name="ignoreAcceptHeader" value="true" />
</bean>

<!-- If no extension matched, use JSP view -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
  <property name="order" value="2" />
  <property name="prefix" value="/WEB-INF/jsp/"/>
  <property name="suffix" value=".jsp"/>
</bean>

How do i now select either XML or JSON? localhost:8080/spring-json/sometestclass/status ? localhost:8080/spring-json/sometestclass/status.xml ? localhost:8080/spring-json/sometestclass/status.json ?

None of the examples above are working, but i can force the response-format with the Accept-header "application/xml" or "application/json" ... if i do the following...

@RequestMapping(value = "/status", method = RequestMethod.GET, headers = "Accept=application/xml, application/json")
public @ResponseBody Web_ServerStatus isServerAlive() {
    Web_ServerStatus l_ReturnObj = new Web_ServerStatus();

...i only get XML back.

What's the problem i am running into?

Thanks in advance!

Yes, take a look at ContentNegotiatingViewResolver (since you included spring as a tag).

Here's a link: http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/mvc.html#mvc-multiple-representations.

But, REST does not imply XML. Depending on the client's Accept header and the capabilities of you service, you can render the resource in different ways.

Solution:

@RequestMapping(value = "/status", method = RequestMethod.GET)
public Web_ServerStatus isServerAlive() {
  ...
}

WITHOUT "@ResponseBody"