Date and time regular expression
I'm looking for a regular expression which matches the following datetime format:
dd-MMM-yyyy HH:mm:ss (15-Sep-2011 16:00:47)
Currently I only have the regex for date which looks something like this:
^(3[0-1]|2[0-9]|1[0-9]|0[1-9])[\s{1}|\/|-](Jan|JAN|Feb|FEB|Mar|MAR|Apr|APR|May|MAY|Jun|JUN|Jul|JUL|Aug|AUG|Sep|SEP|Oct|OCT|Nov|NOV|Dec|DEC)[\s{1}|\/|-]\d{4}$
Any ideas for the time part?
It's ok guys I found the solution. Submitting for anyone who wants to utilise it.
(3[0-1]|2[0-9]|1[0-9]|0[1-9])[\s{1}|\/|-](Jan|JAN|Feb|FEB|Mar|MAR|Apr|APR|May|MAY|Jun|JUN|Jul|JUL|Aug|AUG|Sep|SEP|Oct|OCT|Nov|NOV|Dec|DEC)[\s{1}|\/|-]\d{4}\s(20|21|22|23|[0-1]?\d):[0-5]?\d:[0-5]?开发者_高级运维\d
Must it be a regex?
DateTime.TryParseExact will work much better.
DateTime myDate;
// dd-MMM-yyyy HH:mm:ss (15-Sep-2011 16:00:47)
if (DateTime.TryParseExact(dateAsString,
"dd-MMM-yyyy HH:mm:ss",
new CultureInfo("en-US"),
DateTimeStyles.None,
out myDate))
{ ... }
Err, it appears to me that the date bit is the hard one :-) But you can use the same methods for the time.
Assuming you have two fixed digits, you can use something like:
(([01][0-9])|(2[0-3])):[0-5][0-9]:[0-5][0-9]
The first bit is the slightly tricky bit since you want one of:
0
or1
followed by a digit.2
followed by0
thru3
.
The minutes and seconds are both:
0
thru5
followed by0
thru9
.
If you want to allow single-digit hours, just replace [01]
with [01]?
.
You may also want to consider the possibility that people may enter nov
or OcT
as the month, rendering your regex less useful.
This could be solved with a case-insensitive version which would also reduce the size of the regex as well, requiring only one string per month.
As Joel suggested above that I should add my solution as an answer here. So here it is:
(3[0-1]|2[0-9]|1[0-9]|0[1-9])[\s{1}|\/|-](Jan|JAN|Feb|FEB|Mar|MAR|Apr|APR|May|MAY|Jun|JUN|Jul|JUL|Aug|AUG|Sep|SEP|Oct|OCT|Nov|NOV|Dec|DEC)[\s{1}|\/|-]\d{4}\s(20|21|22|23|[0-1]?\d):[0-5]?\d:[0-5]?\d
Do let me know if it works out.
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