Xml serialization - Change the serialization type of xml

I have a struct like this:

public struct Vehicles
{
    public string Name { get; set; }
    public string Count { get; set; }
    public List<Car> Cars { get; set; }
}

public struct Car
{
    public string Name { get; set; }
    public int Count { get; set; }
    public List<Tire> Tires { get; set; }
}

public struct Tire
{
    public string Brand { get; set; }
    public int Count { get; set; }
    public int UniqueCount { get; set; }
    public List<Dimension> Dimensions { get; set; }
}

public struct Dimension
{
    public string Size { g开发者_StackOverflow中文版et; set; }
    public int AlternateSize { get; set; }
}

When I serialize "Vehicles" it is like:

<root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:xsd="http://www.w3.org /2001/XMLSchema">
  <Vehicles>
    <Name>SuperVehicles</Name>
    <Cars>
      <Car>
        <Name>BMW</Name>
        <Count>29</Count>
        <Tires>
          <Tire>
            <Name>DMZ</Name>
            <Count>26</Count>
            <UniqueCount>24</UniqueCount>
            <Dimensions>
              <Dimension>
                <Size>70x570</Size>
                <AlternateSize>70x580</AlternateSize>
              </Dimension>
              <Dimension>
                <Size>60x570</Size>
                <AlternateSize>60x580</AlternateSize>
              </Dimension>
              <Dimension>
                <Size>50x570</Size>
                <AlternateSize>50x580</AlternateSize>
              </Dimension>
            </Dimensions>
          </Tire>
        </Tires>
      </Car>
    </Cars>
  </Vehicles>
</root>

Now the problem is, I want to serialize it like this:

<root>
  <vehicles vehicleName="superVehicles" vehicleCount="50" carName="BMW"
      carCount="25" tireBrand="kamu" tireCount="15" tireUniqueCount="15"
      dimensionSize="70x570" dimensionAlternateSize="70x580" />
  <vehicles vehicleName="superVehicles" vehicleCount="35" carName="MERCEDES"
      carCount="22" tireBrand="kamu" tireCount="12" tireUniqueCount="12"
      dimensionSize="60x570" dimensionAlternateSize="60x580" />
  <vehicles vehicleName="superVehicles" vehicleCount="35" carName="PORSCHE"
      carCount="22" tireBrand="kamu" tireCount="12" tireUniqueCount="12"
      dimensionSize="60x570" dimensionAlternateSize="60x580" />
</root>

Do I have to change the structure and avoid the groupings or is there any way to create a schema for xml serialization to gather this result.

Summary: I get all the child items in a new tag when I serialize the root struct to xml but I need to take them as properties of an instance that create only the count of root (Vehicles in this situation) element of rows to xml.

You need to do manual serialization.

Here is how you can implement this using System.Xml.Linq :

var xmlElementsVehicles  = new[]{
                                  new XElement("vehicles ", new object[]
                                  {
                                   new XElement("vehicleName", "superVehicles"),
                                   new XElement("vehicleCount", 35),
                                   new XElement("carName", "PORSCHE"),
                                   new XElement("carCount", 2)
                                  }),
                                  new XElement("vehicles ", new object[]
                                  {
                                   new XElement("vehicleName", "superVehicles"),
                                   new XElement("vehicleCount", 35),
                                   new XElement("carName", "PORSCHE"),
                                   new XElement("carCount", 2)
                                  })
                                };
var root = new XElement("root", xmlElementsVehicles );
var myXml = new XDocument(new XDeclaration("1.0", "utf-8", "yes"), root);
using (var xmlWriter = XmlWriter.Create(stream))
{
  myXml.Save(xmlWriter);
}

To use XmlSerializer the model must roughly be the same as the layout; a few things can change (names, etc). However, your model is nothing like the XML. Three options, then:

• create a second DTO model that looks like the XML (you can use xsd.exe on the sample XML to automate this), and use XmlSerializer
• don't use XmlSerializer, but build the XML somehow else (XmlDocument or XDocument would be the obvious two, or XmlWriter if the size is very large)
• use something like xslt to reshape the XML after writing

There is nothing "easy" can be done to make XmlSerializer write that model into your desired XML.