How to echo out php code that will execute?
I am making a website and would want to do the following, but I have no idea how: echo out HTML code with PHP code, so the PHP code executes. I read the file and echo it, but the PHP code is just a string of text and does not execute.
For example:
[a website file dude.php]
<html>
<?php
echo "dude";
?>
</html>
[another website file, that tries to echo out dude.php file, with the PHP code executed]
<?php
$pathToFile = 'dude.php';
$myFile = fopen($pathToFile, 'r');
$theData = fread($myFile, filesize($pathToFile));
echo $theData;
fclose($myFile);
?>
But all I get, is dude.php echoed out with the PHP code not executed.
I do not understand why, maybe there is something with the "ec开发者_如何学Goho" command...
I hope that this was clear enough for people to understand. I really don't know any other way to explain it.
You're looking for the include statement.
Evaluate string code wiht eval($somePhpCode). -Documentation- But maybe you want to use include as well.
加载中,请稍侯......
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