How to read an entire file to a string using C#?
What is the quickest way to read a text file into a开发者_运维知识库 string variable?
I understand it can be done in several ways, such as read individual bytes and then convert those to string. I was looking for a method with minimal coding.
How about File.ReadAllText
:
string contents = File.ReadAllText(@"C:\temp\test.txt");
A benchmark comparison of File.ReadAllLines
vs StreamReader ReadLine
from C# file handling
Results. StreamReader is much faster for large files with 10,000+ lines, but the difference for smaller files is negligible. As always, plan for varying sizes of files, and use File.ReadAllLines only when performance isn't critical.
StreamReader approach
As the File.ReadAllText
approach has been suggested by others, you can also try the quicker (I have not tested quantitatively the performance impact, but it appears to be faster than File.ReadAllText
(see comparison below)). The difference in performance will be visible only in case of larger files though.
string readContents;
using (StreamReader streamReader = new StreamReader(path, Encoding.UTF8))
{
readContents = streamReader.ReadToEnd();
}
Comparison of File.Readxxx() vs StreamReader.Readxxx()
Viewing the indicative code through ILSpy I have found the following about File.ReadAllLines
, File.ReadAllText
.
File.ReadAllText
- UsesStreamReader.ReadToEnd
internallyFile.ReadAllLines
- Also usesStreamReader.ReadLine
internally with the additionally overhead of creating theList<string>
to return as the read lines and looping till the end of file.
So both the methods are an additional layer of convenience built on top of StreamReader
. This is evident by the indicative body of the method.
File.ReadAllText()
implementation as decompiled by ILSpy
public static string ReadAllText(string path)
{
if (path == null)
{
throw new ArgumentNullException("path");
}
if (path.Length == 0)
{
throw new ArgumentException(Environment.GetResourceString("Argument_EmptyPath"));
}
return File.InternalReadAllText(path, Encoding.UTF8);
}
private static string InternalReadAllText(string path, Encoding encoding)
{
string result;
using (StreamReader streamReader = new StreamReader(path, encoding))
{
result = streamReader.ReadToEnd();
}
return result;
}
string contents = System.IO.File.ReadAllText(path)
Here's the MSDN documentation
For the noobs out there who find this stuff fun and interesting, the fastest way to read an entire file into a string in most cases (according to these benchmarks) is by the following:
using (StreamReader sr = File.OpenText(fileName))
{
string s = sr.ReadToEnd();
}
//you then have to process the string
However, the absolute fastest to read a text file overall appears to be the following:
using (StreamReader sr = File.OpenText(fileName))
{
string s = String.Empty;
while ((s = sr.ReadLine()) != null)
{
//do what you have to here
}
}
Put up against several other techniques, it won out most of the time, including against the BufferedReader.
Take a look at the File.ReadAllText() method
Some important remarks:
This method opens a file, reads each line of the file, and then adds each line as an element of a string. It then closes the file. A line is defined as a sequence of characters followed by a carriage return ('\r'), a line feed ('\n'), or a carriage return immediately followed by a line feed. The resulting string does not contain the terminating carriage return and/or line feed.
This method attempts to automatically detect the encoding of a file based on the presence of byte order marks. Encoding formats UTF-8 and UTF-32 (both big-endian and little-endian) can be detected.
Use the ReadAllText(String, Encoding) method overload when reading files that might contain imported text, because unrecognized characters may not be read correctly.
The file handle is guaranteed to be closed by this method, even if exceptions are raised
string text = File.ReadAllText("Path");
you have all text in one string variable. If you need each line individually you can use this:
string[] lines = File.ReadAllLines("Path");
System.IO.StreamReader myFile =
new System.IO.StreamReader("c:\\test.txt");
string myString = myFile.ReadToEnd();
if you want to pick file from Bin folder of the application then you can try following and don't forget to do exception handling.
string content = File.ReadAllText(Path.Combine(System.IO.Directory.GetCurrentDirectory(), @"FilesFolder\Sample.txt"));
@Cris sorry .This is quote MSDN Microsoft
Methodology
In this experiment, two classes will be compared. The StreamReader
and the FileStream
class will be directed to read two files of 10K and 200K in their entirety from the application directory.
StreamReader (VB.NET)
sr = New StreamReader(strFileName)
Do
line = sr.ReadLine()
Loop Until line Is Nothing
sr.Close()
FileStream (VB.NET)
Dim fs As FileStream
Dim temp As UTF8Encoding = New UTF8Encoding(True)
Dim b(1024) As Byte
fs = File.OpenRead(strFileName)
Do While fs.Read(b, 0, b.Length) > 0
temp.GetString(b, 0, b.Length)
Loop
fs.Close()
Result
FileStream
is obviously faster in this test. It takes an additional 50% more time for StreamReader
to read the small file. For the large file, it took an additional 27% of the time.
StreamReader
is specifically looking for line breaks while FileStream
does not. This will account for some of the extra time.
Recommendations
Depending on what the application needs to do with a section of data, there may be additional parsing that will require additional processing time. Consider a scenario where a file has columns of data and the rows are CR/LF
delimited. The StreamReader
would work down the line of text looking for the CR/LF
, and then the application would do additional parsing looking for a specific location of data. (Did you think String. SubString comes without a price?)
On the other hand, the FileStream
reads the data in chunks and a proactive developer could write a little more logic to use the stream to his benefit. If the needed data is in specific positions in the file, this is certainly the way to go as it keeps the memory usage down.
FileStream
is the better mechanism for speed but will take more logic.
well the quickest way meaning with the least possible C# code is probably this one:
string readText = System.IO.File.ReadAllText(path);
you can use :
public static void ReadFileToEnd()
{
try
{
//provide to reader your complete text file
using (StreamReader sr = new StreamReader("TestFile.txt"))
{
String line = sr.ReadToEnd();
Console.WriteLine(line);
}
}
catch (Exception e)
{
Console.WriteLine("The file could not be read:");
Console.WriteLine(e.Message);
}
}
string content = System.IO.File.ReadAllText( @"C:\file.txt" );
You can use like this
public static string ReadFileAndFetchStringInSingleLine(string file)
{
StringBuilder sb;
try
{
sb = new StringBuilder();
using (FileStream fs = File.Open(file, FileMode.Open))
{
using (BufferedStream bs = new BufferedStream(fs))
{
using (StreamReader sr = new StreamReader(bs))
{
string str;
while ((str = sr.ReadLine()) != null)
{
sb.Append(str);
}
}
}
}
return sb.ToString();
}
catch (Exception ex)
{
return "";
}
}
Hope this will help you.
you can read a text from a text file in to string as follows also
string str = "";
StreamReader sr = new StreamReader(Application.StartupPath + "\\Sample.txt");
while(sr.Peek() != -1)
{
str = str + sr.ReadLine();
}
I made a comparison between a ReadAllText and StreamBuffer for a 2Mb csv and it seemed that the difference was quite small but ReadAllText seemed to take the upper hand from the times taken to complete functions.
I'd highly recommend using the File.ReadLines(path) compare to StreamReader or any other File reading methods. Please find below the detailed performance benchmark for both small-size file and large-size file. I hope this would help.
File operations read result:
For small file (just 8 lines)
For larger file (128465 lines)
Readlines Example:
public void ReadFileUsingReadLines()
{
var contents = File.ReadLines(path);
}
Note : Benchmark is done in .NET 6.
This comment is for those who are trying to read the complete text file in winform using c++ with the help of C# ReadAllText function
using namespace System::IO;
String filename = gcnew String(charfilename);
if(System::IO::File::Exists(filename))
{
String ^ data = gcnew String(System::IO::File::RealAllText(filename)->Replace("\0", Environment::Newline));
textBox1->Text = data;
}
精彩评论