how to show single dot using custom Number pad in iphone?
i am creating custom NumberPad
if (([[[UIDevice currentDevice] systemVersion] doubleValue] >= 4.1)) {
inputBoxTextField.keyboardType = UIKeyboardTypeDecimalPad;
}
my problem is, i want to display dot only one time.
than开发者_运维知识库ks in advance.
If you want to allow the user to enter only one dot, you can use the delegate method
-(BOOL) textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string
And simply check if the textField already contains a dot.
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
NSNumber* candidateNumber;
NSString* candidateString = [textField.text stringByReplacingCharactersInRange:range withString:string];
range = NSMakeRange(0, [candidateString length]);
[numberFormatter getObjectValue:&candidateNumber forString:candidateString range:&range error:nil];
if (([candidateString length] > 0) && (candidateNumber == nil || range.length < [candidateString length])) {
return NO;
}
else {
return YES; } }
I use the following code. Works perfectly for me and with less code.
- (BOOL)textField:(UITextField *)textField shouldChangeCharactersInRange:(NSRange)range replacementString:(NSString *)string {
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
NSString *decimalSymbol = [numberFormatter decimalSeparator];
if(([textField.text rangeOfString:decimalSymbol].location != NSNotFound) &&
([string rangeOfString:decimalSymbol].location != NSNotFound)) {
return NO;
}
return YES;
}
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