How can I get the content of this string surrounded by single-quote
I have a string like this:
SOMETHING='abc.abc.abc'
开发者_开发技巧
How can I extract the content of it ( abc.abc.abc ), inside the single-quotes?
$ awk -F"=\047|\047" '/SOMETHING/{print $(NF-1)}' file
abc.abc.abc
str="SOMETHING='abc.abc.abc'"
substr=$(echo "$str" | cut -d "'" -f 2)
With bash, you could write
substr=$(cut -d "'" -f 2 <<< "$str")
Or, shell only:
IFS="'"
set -- $str
substr=$2
Or use an array
IFS="'"
fields=($str)
substr=${fields[1]}
You should be able to already extract it. Example:
$ cat test.sh
#!/bin/bash
SOMETHING='abc.abc.abc'
echo $SOMETHING
$ ./test.sh
abc.abc.abc
You have tagged this question as shell. So I guess you're able to use regular expressions in grep. Or perhaps you could do something with javascript regular expressions.
this regex would find it
abc\.abc\.abc
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