Spring form not submitting
I am using Spring SimpleFormController for my forms and for some reason it won't go to the onSubmit method
Here's my code:
public class CreateProjectController extends SimpleFormController {
ProjectDao projectDao;
public CreateProjectController() {
setCommandClass(Project.class);
setCommandName("Project");
setSessio开发者_高级运维nForm(true);
}
@Override
protected Object formBackingObject(HttpServletRequest request)
throws Exception {
String id = request.getParameter("id");
Project project = projectDao.getProjectByOutsideId(id);
System.out.println("@formbacking object method");
System.out.println("the success view is "+getSuccessView());
return project;
}
@Override
protected ModelAndView onSubmit(Object command) throws Exception {
Project project = (Project) command;
System.out.println("this is the project title: "+project.getTitle());
System.out.println("the success view is "+getSuccessView());
projectDao.insert(project);
return new ModelAndView(getSuccessView());
}
I know because it prints "@formbacking object method" string but not the "the success view is..." string and the :"this is the pr..." string. I see "@formback.." string in the console but not the last two whenever I hit submit. I don't know where the problem is.
This is my jsp
<form:form method="POST" commandName="Project">
Name: <form:input path="title"/><br/>
Description: <form:input path="description"/><br/>
Link: <form:input path="url" disabled="true"/><br/>
Tags: <form:input path="tags"/><br/>
Assessors <form:input path="assessors"/><br/><br/>
<input type="submit" value="submit"/>
</form:form>
I am running on Google App Engine btw. Maybe the problem is there?
UPDATE: The problem seems to be with the formBackingObject method. When I removed it, the form now goes to the onSubmit when I click submit.
But I'd like to have values from of the command class from the database in my forms.
Another piece of code that doesn't work:
@Override
protected Object formBackingObject(HttpServletRequest request)
throws Exception {
String id = request.getParameter("id");
Project projectFromConsumer = projectDao.getProjectByOutsideId(id);
Project project = new Project();
String title = projectFromConsumer.getTitle();
project.setTitle(title);
project.setUrl("projectUrl");
return project;
}
but this does work:
@Override
protected Object formBackingObject(HttpServletRequest request)
throws Exception {
String id = request.getParameter("id");
Project projectFromConsumer = projectDao.getProjectByOutsideId(id);
Project project = new Project();
String title = projectFromConsumer.getTitle();
project.setTitle("projectTitle");
project.setUrl("projectUrl");
return project;
}
Now I am really confused. haha.
I was thinking along the same lines as axtavt. You are only going to have an id request parameter on updates, so you should add some code for creation forms:
FYI, formBackingObject requires a non-null object to be returned. To save some memory, you can have a final constant member variable that is the default return value. Your code satisfies this though since you're transferring objects, but I don't get why you're transferring data (creating an extra object) when you're not using a DTO. You could simply do this:
private final static Project PROJECT_INSTANCE = new Project();
static {
PROJECT_INSTANCE.setTitle("defaultProjectTitle");
}
@Override
protected Project formBackingObject(HttpServletRequest request) throws Exception {
String id = request.getParameter("id");
if(id == null || id.trim().length() == 0 || !id.matches("\\d+")) {
return PROJECT_INSTANCE;
}
return projectDao.getProjectByOutsideId(id);
}
You don't need a hidden id input field. You would use formBackingObject()
for initializing the form input fields for updating (by navigating to page.jsp?id=111).
Look at the String id = request.getParameter("id");
. There is no such field in your form, so probably you get an error there during submit process, maybe, getProjectByOutsideId
returns null
.
P.S. It's strange that your formBackingObject
is executing when you press submit, it shouldn't if you really set setSessionForm(true)
.
Try turning the spring debugging up. It provides a lot of information, which can be helpful. Do this by editing the log4j.properties file.
log4j.logger.org.springframework=DEBUG
Have you added logging to make sure the formBackingObject is returning something?
System.out.println("@formbacking object method is returning: " + project);
It will make sure something is being returned. In general the formBackingObject should always return something.
EDIT:
Id is not being passed during submission in the snippet. Maybe it is during the load, e.g. /page.do?id=4, but it doesn't appear in the form.
Add <form:hidden path="id"/>
to your form during on submit. Otherwise the id will not be a parameter and the getProjectByOutsideId will fail.
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