Finding words in brackets that contain a single char using regex

I'm trying to find all words which are enclosed in double brackets and contain a bracket in the middle of the 开发者_高级运维word, I am using Java.

I have this so far but its not quite working.

\\[\\[[\\[|\\]]\\]\\]

Any suggestions?

For this sample input "hello [[wo[orld]]", I'd like to find "[[wo[orld]]".

This should do:

String str = "hello [[wo[orld]]";

Pattern p = Pattern.compile("\\[\\[[^\\[\\]]*[\\[\\]][^\\[\\]]*\\]\\]");
Matcher m = p.matcher(str);

if (m.find())
    System.out.println(m.group(0));

Output:

[[wo[orld]]

Pattern breakdown:

• \[\[          -- Two initial [[ (you got that right already!)
• [^\[\]]*  -- Something else than [ and ] zero or more times
• [\[\]]      -- The "middle" bracket symbol
• [^\[\]]*  -- Something else than [ and ] zero or more times
• \]\]          -- Two closing ]] (that one you figured out as well)

If you want to capture what's in the double brackets and if you don't care whether or not there are other non-bracket characters around the single bracket, try:

(\[\[[^\[\]]*\[[^\[\]]*\]\])

Otherwise, if there must be at least one non-bracket character around the innermost bracket, change the asterisks to plusses, aka:

(\[\[[^\[\]]+\[[^\[\]]+\]\])

The term bracket is a bit overloaded but I assume you are trying to match strings of the form:

[[some[thing]]

String sampleString = "[[some[thing]]";
System.out.println(Pattern.matches("\\[\\[.*\\[.*\\]\\]", sampleString)); //true

Pattern.matches() is a static method that returns true for a match, otherwise false