开发者

How to create a delay in Swing

I made a blackjack game, and I want the AI player to pause between taking cards. I tried simply using Thread.sleep(x), but that makes it freeze until the AI player is done taking all of his cards. I know that Swing is not thread safe, so I looked at Timers, but I could not understand how I could use one for this. Here is my current code:

while (JB.total < 21) {

          try {
            Thread.sleep(1000);
          } catch (InterruptedException ex) {
            System.out.println("Oh noes!");
          }

          switch (getJBTable(JB.total, JB.aces > 0)) {
            case 0:
              JB.hit();
  开发者_JAVA百科            break;
            case 1:
              break done;
            case 2:
              JB.hit();
              JB.bet *= 2;
              break done;
          }
        }

BTW, the hit(); method updates the GUI.


so I looked at Timers, but I could not understand how I could use one for this

The Timer is the solution, since as you say you are updating the GUI which should be done on the EDT.

I'm not sure what your concern is. You deal a card and start the Timer. When the Timer fires you decide to take another card or hold. When you hold your stop the Timer.


Well, the following code shows a JFrame with a JTextArea and a JButton. When the buttons is clicked, the Timer send the event repeatedly (with a second delay between them) to the actionListener related to the button which appends a line with the current time.

import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Calendar;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JTextArea;
import javax.swing.Timer;


public class TimerTest extends JFrame implements ActionListener{

    private static final long serialVersionUID = 7416567620110237028L;
    JTextArea area;
    Timer timer;
    int count; // Counts the number of sendings done by the timer
    boolean running; // Indicates if the timer is started (true) or stopped (false)

    public TimerTest() {
        super("Test");
        setBounds(30,30,500,500);
        setDefaultCloseOperation(EXIT_ON_CLOSE);
        setLayout(null);

        area = new JTextArea();
        area.setBounds(0, 0, 500, 400);
        add(area);

        JButton button = new JButton("Click Me!");
        button.addActionListener(this);
        button.setBounds(200, 400, 100, 40);
        add(button);

        // Initialization of the timer. 1 second delay and this class as ActionListener
        timer = new Timer(1000, this);
        timer.setRepeats(true); // Send events until someone stops it
        count = 0; // in the beginning, 0 events sended by timer
        running = false;
        System.out.println(timer.isRepeats());
        setVisible(true); // Shows the frame
    }

    public void actionPerformed(ActionEvent e) {
        if (! running) {
            timer.start();
            running = true;
        }
        // Writing the current time and increasing the cont times
        area.append(Calendar.getInstance().getTime().toString()+"\n");
        count++;
        if (count == 10) {
            timer.stop();
            count = 0;
            running = false;
        }
    }

    public static void main(String[] args) {
        // Executing the frame with its Timer
        new TimerTest();
    }
}

Well, this code is a sample of how to use javax.swig.Timer objects. In relation with the particular case of the question. The if statement to stop the timer must change, and, obviously, the actions of the actionPerformed. The following fragment is a skeleton of the solution actionPerformed:

public void actionPerformed(ActionEvent e) {
    if (e.getComponent() == myDealerComponent()) {
    // I do this if statement because the actionPerformed can treat more components
        if (! running) {
            timer.start();
            runnig = true;
        }
        // Hit a card if it must be hitted
        switch (getJBTable(JB.total, JB.aces > 0)) {
          case 0:
              JB.hit();
              break;
          case 1:
              break done;
          case 2:
              JB.hit();
              JB.bet *= 2;
              break done;
        }
        if (JB.total >= 21) { // In this case we don't need count the number of times, only check the JB.total 21 reached
            timer.stop()
            running = false;
        }

    }
}

IMHO this resolves the problem, now @user920769 must think where put the actionListener and the starting/stopping conditions...

@kleopatra: Thanks for show me the existence of this timer class, I don't know nothing about it and it's amazing, make possible a lot of tasked things into a swing application :)


Well, a quick explanation about Timers.

First of all, you need a java.util.Timer variable in your class and another class in your project which extends from java.util.TimerTask (let's call it Tasker).

The initialization of the Timer variable is so easy:

Timer timer = new Timer();

Now the Tasker class:

public class Tasker extends TimerTask {
    @Override
    public void run() {
        actionToDo(); // For example take cards 
    }

    // More functions if they are needed
}

Finally, the installation of the timer with its related Tasker:

long delay = 0L;
long period = pauseTime;
timer.schedule(new Tasker(),delay,period);

The schedule function indicates the following: Fisrt param: Action to do each period milliseconds (Executes the run function of a TimerTask class or its extension) Second param: When the timer must start. In this case, it starts when the schedule function is called. The following example indicates a starting 1 second after call the schedule function: timer.schedule(new Tasker(),1000,period); Third param: milliseconds between one call of Tasker.run() function and the following call.

I hope you understand this microtutorial :). If you have any problem, ask for more detailed information!

Kind regards!


I think that in this tutorial is clear how to use Timers in order to achieve what you want, without having to deal with Threads.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜