XML to XML Mapping using XSLT
I am new to XSLT and trying to map one XML to another XML using xslt, here is my first XML
<root>
<record>
<element name="LoginId">a</element>
<element name="name">Admin Manager</element>
<element name="password">12345</element>
<element name="Age">28</element>
<element name="Sex">M</element>
</record>
<record>
<element name="LoginId">b</element>
<element name="name">HR exec</element>
<element name="password">pass1</element>
<element name="Age">26</element>
<element name="Sex">F</element>
</record>
<record>
<element name="LoginId">c</element>
<element name="name">PR Manager</element>
<element name="password">pass2</element>
<element name="Age">27</element>
<element name="Sex">M</element>
</record>
</root>
I need to convert this XML to the following
<?xml version="1.0" encoding="UTF-8"?>
<final>
<test>
<UID>a</UUID>
<Name>HR manager</Name>
<Groups>admingroup</Groups>
<Password>12345</Password>
</test>
<test>
<UID>b</UUID>
<Name>HR exec</Name>
<Groups>admingroup</Groups>
<Password>pass1</Password>
</test>
<test>
<UID>c</UUID>
<Name>PR manager</Name>
<Groups>admingroup</Groups>
<Password>pass2</Password>
</test>
</final>
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i tried following xslt for transformation
<?xml version="1.0" encoding="UTF-8" ?>
- <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
- <xsl:template match="/">
- <test>
- <xsl:for-each select="root/record">
<xsl:apply-templates select="element" />
</xsl:for-each>
</test>
</xsl:template>
- <xsl:template match="element">
- <test>
<Employee />
- <UID>
<xsl:value-of select="@LoginId" />
</UID>
- <xsl:choose>
- <xsl:when test="@name = ''">
- <Name>
<xsl:text>demo employee</xsl:text>
</Name>
</xsl:when>
- <xsl:otherwise>
- <Name>
<xsl:value-of select="@name" />
</Name>
</xsl:otherwise>
</xsl:choose>
- <Groups>
<xsl:text>admingroup</xsl:text>
</Groups>
- <Password>
<xsl:value-of select="@password" />
</Password>
</test>
</xsl:template>
</xsl:transform>
but this xslt is generating following XML output
<?xml version="1.0" encoding="UTF-8"?>
<impex>
<final>
<Employee />
<UID />
<Name>LoginId</Name>
<Groups>admingroup</Groups>
<Password />
</final>
total 15 <final></final> with similar output
i can do it easily in Java but some how have to do in xslt and only problem i am facing is the repetition of <element>
tag with different attribute values
any help in this regard will be much helpful for me
Even if you already have the excellent solution proposed by @Martin's answer (+1), I'm fixing here your transform to show you where you were wrong. This might help you in learning a bit more of how XSLT (and XPath) works.
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<final>
<xsl:apply-templates select="root/record" />
</final>
</xsl:template>
<xsl:template match="record">
<test>
<Employee />
<UID>
<xsl:value-of select="element[@name='LoginId']" />
</UID>
<xsl:choose>
<xsl:when test="element[@name='name']=''">
<Name>
<xsl:text>demo employee</xsl:text>
</Name>
</xsl:when>
<xsl:otherwise>
<Name>
<xsl:value-of select="element[@name='name']"/>
</Name>
</xsl:otherwise>
</xsl:choose>
<Groups>
<xsl:text>admingroup</xsl:text>
</Groups>
<Password>
<xsl:value-of select="element[@name='password']" />
</Password>
</test>
</xsl:template>
</xsl:transform>
Note that xsl:choose
approach is correct, even if normally the preferable XSLT way is template rules:
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<final>
<xsl:apply-templates select="root/record" />
</final>
</xsl:template>
<xsl:template match="record">
<test>
<Employee />
<UID>
<xsl:value-of select="element[@name='LoginId']" />
</UID>
<Name>
<xsl:apply-templates select="element[@name='name']"/>
</Name>
<Groups>
<xsl:text>admingroup</xsl:text>
</Groups>
<Password>
<xsl:value-of select="element[@name='password']" />
</Password>
</test>
</xsl:template>
<xsl:template match="element[@name='name'][.='']">
<xsl:text>demo employee</xsl:text>
</xsl:template>
<xsl:template match="element[@name='name'][.!='']">
<xsl:value-of select="."/>
</xsl:template>
</xsl:transform>
I would approach it like this:
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>
<xsl:template match="root">
<final>
<xsl:apply-templates/>
</final>
</xsl:template>
<xsl:template match="record">
<test>
<xsl:apply-templates select="element[@name = ('LoginId', 'name')]"/>
<Groups>admingroup</Groups>
<xsl:apply-templates select="element[@name = 'password']"/>
</test>
</xsl:template>
<xsl:template match="element[@name = 'LoginId']">
<UID>
<xsl:value-of select="."/>
</UID>
</xsl:template>
<xsl:template match="element[@name = 'name']">
<Name>
<xsl:value-of select="."/>
</Name>
</xsl:template>
<xsl:template match="element[@name = 'password']">
<Password>
<xsl:value-of select="."/>
</Password>
</xsl:template>
</xsl:stylesheet>
That way Saxon 9.3 generates the following result from your sample input:
<final>
<test>
<UID>a</UID>
<Name>Admin Manager</Name>
<Groups>admingroup</Groups>
<Password>12345</Password>
</test>
<test>
<UID>b</UID>
<Name>HR exec</Name>
<Groups>admingroup</Groups>
<Password>pass1</Password>
</test>
<test>
<UID>c</UID>
<Name>PR Manager</Name>
<Groups>admingroup</Groups>
<Password>pass2</Password>
</test>
</final>
Use Source Schema to Destination Schema with Transform Maps. XSLT is better suited for transforming XML into other formats, for the sake of presenting data..
Checkout BizTalk
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