MySQL Select Group By and Order By

Here is the SQL Statement that I am using..

$sql = "SELECT surname, forename, count(*) FROM people WHERE user_id='$user_id'
        GROUP BY surname ORDER BY time";

$result = mysql_query($sql);
$count=mysql_num_rows($result);

if($count > 0){
while($row = mysql_fetch_array($result)) {
$i = $i +1;
$person[$i] = $row['surname'].'&&'.$row['forename'];
} 

What 开发者_JS百科I would like to get is all the entries from the people database relative to user_id grouped by surname and ordered by the time that they were entered in to the database. e.g.

12:00  Smith  James
13:00  Smith  Linda
14:00  Smith  Sam

12:30  OtherSurname  Lydia
13:30  OtherSurname  Harry
14:30  OtherSurname  Phil

The problem at the moment is that I only get one result for each surname. How can I use the SELECT statement with GROUP BY and ORDER BY to get all of the entries? thank you.

Change your GROUP BY to:

GROUP BY surname, forename

You don't need to group by surname, you need to order by surname

ORDER BY surname,time