Same function name , one with const at the tail
Given the following code :
#include <iostream>
using namespace std;
class A
{
public:
virtual void func() {cout << "func A" << endl;}
};
class B : public A
{
public:
void func() const {cout << "func B" << endl;}
};
int main()
{
A *pa = new B;
pa->func();
B *pb = new 开发者_开发问答B;
pb->func();
return 0;
}
output is :
func A // pa->func();
func B // pb->func();
Why,when doing pb->func();
the method of B would work and not the other one (that B inherited from A) ?
thanks ,Ronen
The method in B does not override the method in A so the virtual declaration shouldn't (as it doesn't) cause the method in B to be called. Consider:
class foo
{
public:
void bar();
void bar() const;
}
These are two different methods, one called for a non-const object and the other for a const object.
In order for your code to work as you want, the method in A must also be declared const.
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