Xslt using a wildcard when selecting by attribute

so I have this assignment and they are asking for data given by Xslt

This is what I've got:

<xsl:apply-templates开发者_StackOverflow社区 select="results/result[@name=$param0]"/>

So the $param0 is given by a jquery transform function. My problem is how can I select all of the @name when sending a certain value for $param0? I've tried most wildcards but nothing seems to work. Can you guys help me?

input XML

<results>
 <result name="name1">
  <score>2500</score>
 </result>
 <result name="name2">
  <score>13500</score>
 </result>
 <result name="name3">
  <score>65100</score>
 </result>
</results>

output for $param0="name1"

<result name="name1">
 <score>2500</score>
</result>

So i would have to get all of the scores, I need to keep the xslt statement so I can still select one.

output for $param0="wildcard" <== I need some kind of wildcard (have tried alot of them)

 <result name="name1">
  <score>2500</score>
 </result>
 <result name="name2">
  <score>13500</score>
 </result>
 <result name="name3">
  <score>65100</score>
 </result>

I hope this makes a it clearer what I'm looking for...

Why not using a fake string wildcard?

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output indent="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:param name="param0" select="'*'"/>

    <xsl:template match="/">
        <xsl:copy-of select="results/result[@name=$param0 and $param0!='*']
            |
            results/result[$param0='*']"/>
    </xsl:template>

</xsl:stylesheet>

It copies every result when $param0='*', otherwise it copies the wanted node when there is a match like $param0='name1'; otherwise it does not copy anything at all.

You can use the same expression within xsl:apply-templates.