Get all pairs in a list using LINQ
How do I get all possible pairs of items in a list (order not relevant)?
E.g. if I have
var list = { 1, 2, 3, 4 };
I would like to get these tuples:
var pairs = {
new Tuple(1, 2), new Tuple(开发者_如何学Python1, 3), new Tuple(1, 4),
new Tuple(2, 3), new Tuple(2, 4)
new Tuple(3, 4)
}
Slight reformulation of cgeers answer to get you the tuples you want instead of arrays:
var combinations = from item1 in list
from item2 in list
where item1 < item2
select Tuple.Create(item1, item2);
(Use ToList
or ToArray
if you want.)
In non-query-expression form (reordered somewhat):
var combinations = list.SelectMany(x => list, (x, y) => Tuple.Create(x, y))
.Where(tuple => tuple.Item1 < tuple.Item2);
Both of these will actually consider n2 values instead of n2/2 values, although they'll end up with the correct answer. An alternative would be:
var combinations = list.SelectMany((x, i) => list.Skip(i + 1), (x, y) => Tuple.Create(x, y));
... but this uses Skip
which may also not be optimized. It probably doesn't matter, to be honest - I'd pick whichever one is most appropriate for your usage.
Calculate the Cartesian product to determine all the possible combinations.
For example:
var combinations = from item in list
from item2 in list
where item < item2
select new[] { item, item2 };
You can find more information about calculating a cartesian product using LINQ here:
http://blogs.msdn.com/b/ericlippert/archive/2010/06/28/computing-a-cartesian-product-with-linq.aspx
You can then convert it to a collection of Tuple objects.
var pairs = new List<Tuple<int, int>>();
foreach (var pair in combinations)
{
var tuple = new Tuple<int, int>(pair[0], pair[1]);
pairs.Add(tuple);
}
Or in short:
var combinations = (from item in list
from item2 in list
where item < item2
select new Tuple<int, int>(item, item2)).ToList();
You could solve it like this:
var list = new[] { 1, 2, 3, 4 };
var pairs = from l1 in list
from l2 in list.Except(new[] { l1 })
where l1 < l2
select new { l1, l2 };
foreach (var pair in pairs)
{
Console.WriteLine(pair.l1 + ", " + pair.l2);
}
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