Decimal to hex for int64 in c

Why this code do开发者_如何学Pythones not work ?

#include <iostream>
#include <cstdio>
int main() {
  printf("%X", 1327644190303473294);
}

I am getting o/p 5f264e8e

but expected o/p is 126cbd5b5f264e8e as given by below php script

<?php
  echo dechex(1327644190303473294);
?>

format '%X' expects type 'unsigned int', but argument 2 has type 'long int'

#include <stdio.h>

int main(void) {
    printf("%lX",1327644190303473294);
    return 0;
}

outputs

126CBD5B5F264E8E

The portable way to do this is to

#include <inttypes.h>

And to do:

#include <stdio.h> 
#include <inttypes.h>  // for PRIX64 macro (and INT64_C macro from stdint.h)

int main(void) 
{
    printf("The value is %"PRIX64"\n", INT64_C(1327644190303473294));
    return 0;
}

%X is for int, which is usually 32-bit. The required incantation for a 64-bit number is platform-dependent. On the Mac, it's %qX.

You need to use a different format specifier to indicate that your integer is 64 bits wide. As it stands, your code interprets the input as a 32 bit integer.

In MSVC this would be %I64x, on some platforms it would be %lx and there are indeed other specifiers.

In summary, you need to choose a specifier appropriate for your particular toolset.

for uint64_t, you can try as follow:

uint64_t val = 1327644190303473294;
printf("val: 0x%llx\n", val);