Add leading zeroes to awk variable
I have the following awk command within a "for" loop in bash:
awk -v pdb="$pdb" 'BEGIN {file = 1; filename = pdb"_" file ".pdb"}
/ENDMDL/ {getline; file ++; filename = pdb"_" file ".pdb"}
{print $0 > filename}' < ${pdb}.pdb
This reads a series of files with the name $pdb.pdb and splits them in files called $pdb_1.pdb, $pdb_2.pdb, ..., $pdb_21.pdb, etc. However, I would like to produce files with names like $pdb_01.pdb, $pdb_02.pdb, ..., $pdb_21.pdb, i.e., to add padding z开发者_如何学Ceros to the "file" variable.
I have tried without success using printf in different ways. Help would be much appreciated.
Here's how to create leading zeros with awk
:
# echo 1 | awk '{ printf("%02d\n", $1) }'
01
# echo 21 | awk '{ printf("%02d\n", $1) }'
21
Replace %02
with the total number of digits you need (including zeros).
Replace file
on output with sprintf("%02d", file)
.
Or even the whole assigment with filename = sprintf("%s_%02d.pdb", pdb, file);
.
This does it without resort of printf
, which is expensive. The first parameter is the string to pad, the second is the total length after padding.
echo 722 8 | awk '{ for(c = 0; c < $2; c++) s = s"0"; s = s$1; print substr(s, 1 + length(s) - $2); }'
If you know in advance the length of the result string, you can use a simplified version (say 8 is your limit):
echo 722 | awk '{ s = "00000000"$1; print substr(s, 1 + length(s) - 8); }'
The result in both cases is 00000722
.
Here is a function that left or right-pads values with zeroes depending on the parameters: zeropad(value, count, direction)
function zeropad(s,c,d) {
if(d!="r")
d="l" # l is the default and fallback value
return sprintf("%" (d=="l"? "0" c:"") "d" (d=="r"?"%0" c-length(s) "d":""), s,"")
}
{ # test main
print zeropad($1,$2,$3)
}
Some tests:
$ cat test
2 3 l
2 4 r
2 5
a 6 r
The test:
$ awk -f program.awk test
002
2000
00002
000000
It's not fully battlefield tested so strange parameters may yield strange results.
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