PHP: How to fix array_combine when one valus is empty

How to set a = 0 value for each checkbox unchecked

Error:

Warning: array_combine() [function.array-combine]: Both parameters should have an equal number of elements in

PHP:

$combined = array_combine($_POST['name'], $_POST['day']);

foreach($combined as $name => $value) {
     echo $name.' => '.$value;
}

HTML:

  <form method="post" action="result.php">
  <p>
        <input type="text" name="name[]" value="seth" />
        <input ty开发者_StackOverflow社区pe="checkbox" name="day[]" value="7" />
  </p>

  <p>
        <input type="text" name="name[]" value="jack" />
        <input type="checkbox" name="day[]" value="4" />
  </p>

  <p>
        <input type="text" name="name[]" value="david" />
        <input type="checkbox" name="day[]" value="3" />
  </p>

 </form>

PS:

I won't use:

        <select name="day[]" size="1">
           <option value="0"> Non </option>
           <option value="1"> Yes </option>
        </select>

Your problem is that unchecked checkboxes aren't even sent to the server, so as it is your 2 $_POST arrays won't line up unless they are all checked. You should consider using radios and setting the value of the key in name attribute.

ie do this for each input:

<form>
<p>
    <input type="text" name="name[3]" value="david" />
    <input type="radio" name="day[3]" value="yes" /> <label>Yes</label>
    <input type="radio" name="day[3]" value="no" /><label>No</label>
</p>
</form>

Then do print_r($_POST) and you will see your arrays line up. Another way is to do a hidden input (with exactly the same name="" and it will act as a default value.

Here you go. Hope this works for you. It's a bit more work then what you were hoping for probably.

result.php

<?PHP

$days = array();
$namecount = count($_POST['name']);
for($i = 0; $i < $namecount; $i++){
    $days[$i] = isset($_POST['day'][$i]) ? $_POST['day'][$i] : 0;
}

$arr = array_combine($_POST['name'], $days);
print_r($arr);

?>

form.html

<form method="post" action="result.php">
    <p>
        <input type="text" name="name[]" value="seth" />
        <input type="checkbox" name="day[0]" value="7" />
    </p>

    <p>
        <input type="text" name="name[]" value="jack" />
        <input type="checkbox" name="day[1]" value="4" />
    </p>

    <p>
        <input type="text" name="name[]" value="david" />
        <input type="checkbox" name="day[2]" value="3" />
    </p>
    <input type='submit' value='Submit' />
</form>

I can think of only 3 ways:

1. Move to <input type=radio>s with the same name, this will give you extra control over the content that is sent through. (Given in a previous answer)
2. Add another input, a hidden one, <input type=hidden>, which has the same name as your checkbox, if the checkbox is not selected, the hidden input's value will be sent. (Given in a previous answer)
3. Use JavaScript to submit your form, and loop through the checkboxes to manually test each one for selected state, and send that along with the POST request.