PHP pass variable through URL

I understand how a PHP URL works - I think ... but I'm having problems getting the actual value of the variable to be passed in the example below.

Example

Note: I am adding the below form into a data cell (as part of a table being read via PHP).

$currentrowid = 1;

echo '<td>
  <div class="editdelete">
    <form action="phpindex.php?page=edit&thisrow=<?php echo $currentrowid;?>" method="post">
      <input t开发者_Python百科ype="submit" value="Edit" >
    </form>
  </div>
</td>';

... Some other section of code to read the URL output by the form above:

$val = $_POST['thisrow']; 
echo "the value is: " .$val; //Outputs "$currentrowid"

So, as you can see the code returns the actual name of the variable being passed, NOT the value of the variable being passed.

Any ideas here?

Since you are already within a PHP block, you should not wrap your variable within <?php ... ?>. This will give you an error.

To make this work, you can choose 1 of 2 options:

1) String Concatenation:

echo '... <form action="phpindex.php?page=edit&thisrow='.$currentrowid.'" method="post"> ...';

2) Wrap your string in " (double quotes) instead of ' (single quotes):

echo "... <form action=\"phpindex.php?page=edit&thisrow=$currentrowid\" method=\"post\"> ...";

Note that the second method forces you to escape all the double quotes inside of your string.

2 point.

1. <form action="index.php?thisrow=<?php echo $currentrowid ?>" method="post">
2. You should use $_POST not $_GET to get the post value.

As what was answered above,

<form action="index.php?thisrow=<?php echo $currentrowid; ?>" method="post">

is correct. The reason behind this is you are passing HTML and you have to use an echo from php to output to the html. Otherwise you just get exactly what you put, which is $currentrowid.

Not the easiest, but a quick way to solve your problem. Change your form method to get method="get">, then

$val = $_GET['thisrow'];