How to include only the functions from a php file? [duplicate]

This question already has answers here: Closed 11 years ago.

Possible Duplicate:

Including PHP functions from another file

I'm building code that us开发者_Go百科e function calls that exist in a thirdparty php file. This 3p php file is not a function library but also contain inline code itself.

How do I call the functions without executing the inline code?

edit: duplicate of Including PHP functions from another file ?

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How do I call the functions without executing the inline code?

You can't.

You might be able to suppress the includes' output using output buffering, but the code will still execute.

I don't think there is a good way to do this without making copies of the respective includes, and stripping the inline code from them.

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The simple answer is you can't. A call to include is simply opening the file and running eval() on the content.

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How about splitting the original file into a functions-file and a native code file and including them? This way the original file will work as before and you would be able to include just the functions in your script.

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Theoretically it is possible with evaling of filtered content of file, but filtering code is not an easy task in terms of scripting and performance.

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If all your functions are defined at the top of the file you want to include, you can add a structure like this to it immediately after the function definitions:

if (something that would be true if the file was included) {
  return;
}

For example, if the script doing the include has already defined a variable called $myVar you could do:

if (isset($myVar)) return;

This will cause the included file to stop executing and return control to your original script.

However, the best solution is to create another file called e.g. 'functions.php' and include('functions.php'); in both scripts...