Know if iOS device has cellular data capabilities
I have a toggle in my app that's "download on WiFi only". However, that toggle is useless for iPod 开发者_Python百科touch or WiFi-iPads.
Is there a way to know if the device has cellular data capabilities in code? Something that would work in the future would be great too (like if an iPod touch 5th gen with 3G comes out).
Hi you should be able to check if it has the pdp_ip0 interface
#import <ifaddrs.h>
- (bool) hasCellular {
struct ifaddrs * addrs;
const struct ifaddrs * cursor;
bool found = false;
if (getifaddrs(&addrs) == 0) {
cursor = addrs;
while (cursor != NULL) {
NSString *name = [NSString stringWithUTF8String:cursor->ifa_name];
if ([name isEqualToString:@"pdp_ip0"]) {
found = true;
break;
}
cursor = cursor->ifa_next;
}
freeifaddrs(addrs);
}
return found;
}
This doesn't use any private APIs.
3G by itself seems tough to find. You can find out whether a device can make calls using [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"tel://"]]
. You can check whether a device can get to the internet, period (and by which method that can currently happen) using Reachability code:
NetworkStatus currentStatus = [[Reachability reachabilityForInternetConnection]
currentReachabilityStatus];
if(currentStatus == kReachableViaWWAN) // 3G
else if(currentStatus == kReachableViaWifi) // ...wifi
else if(currentStatus == kNotReachable) // no connection currently possible
..but aside from that, I don't think you can check for the existence of a 3G modem in the device.***** If it can't make a call, and doesn't currently have cell data turned on and wifi turned off, you won't be able to find out if it's 3G-capable.
An alternative way (not forward-compatible though, so you probably don't want to do this) is to compare the device's model with an exhaustive list, knowing which ones have 3G modems in them, as shown here.
***** As per bentech's answer, if you want to go digging around with device names (this may stop working with no advance warning if Apple decide to change the 3g interface name), call getifaddrs
and check for the pdp_ip0
interface.
Swift 3.0 (UIDevice+Extension) of @bentech's answer
Add this line to your BridgingHeader.h:
#import <ifaddrs.h>
Somewhere else:
extension UIDevice {
/// A Boolean value indicating whether the device has cellular data capabilities (true) or not (false).
var hasCellularCapabilites: Bool {
var addrs: UnsafeMutablePointer<ifaddrs>?
var cursor: UnsafeMutablePointer<ifaddrs>?
defer { freeifaddrs(addrs) }
guard getifaddrs(&addrs) == 0 else { return false }
cursor = addrs
while cursor != nil {
guard
let utf8String = cursor?.pointee.ifa_name,
let name = NSString(utf8String: utf8String),
name == "pdp_ip0"
else {
cursor = cursor?.pointee.ifa_next
continue
}
return true
}
return false
}
}
In iOS 6.1, I've been able to use Core Telephony to successfully check for the presence of cellular baseband capabilities. This works on all iPads I tested: Verizon with service activated and without, AT&T with service currently deactivated, SIM card in and out, and a Wi-Fi-only iPad.
The code I used looks like this:
CTTelephonyNetworkInfo* ctInfo = [[CTTelephonyNetworkInfo alloc] init];
CTCarrier* carrier = ctInfo.subscriberCellularProvider;
self.hasWWANCapability = carrier != nil;
For all the iPads with cellular baseband hardware, carrier
is not nil. For the Wi-Fi-only iPad, carrier
is nil.
I'd think you should be able to use the CoreTelephony Framework.
It does call out that it is for carriers to use, so I am not sure if it is against TOS to access it.
Carriers can use this information to write applications that provide services only for their own subscribers
One way of doing it is to ask for the users location. When it is as accurate as possibLe, you will know if the device have GPS. All devices that have GPS will have 3G. And those that don't GPS won't have 3G.
Apple provided code here. https://developer.apple.com/library/ios/samplecode/Reachability/Introduction/Intro.html
You should copy Reachability.h and Reachability.m to your project and import Reachability.h to your class,then
Reachability *networkReachability = [Reachability reachabilityForInternetConnection];
NetworkStatus networkStatus = [networkReachability currentReachabilityStatus];
while (networkStatus==NotReachable) {
NSLog(@"not reachable");
//no internet connection
return;
}
while (networkStatus==ReachableViaWWAN) {
NSLog(@" ReachableViaWWAN ");
}
while (networkStatus==ReachableViaWiFi) {
NSLog(@"ReachableViaWiFi");
}
Another way is to extend this: https://github.com/monospacecollective/UIDevice-Hardware/blob/master/UIDevice-Hardware.m with this:
-(bool) hasCellular:(NSString*)modelIdentifier {
if ([modelIdentifier hasPrefix:@"iPhone"]) return YES;
if ([modelIdentifier hasPrefix:@"iPod"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad1,1"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad2,1"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad2,2"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad2,3"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad2,4"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad2,5"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad2,6"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad2,7"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad3,1"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad3,2"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad3,3"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad3,4"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad3,5"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad3,6"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad4,1"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad4,2"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad2,5"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad2,6"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad2,7"]) return YES;
if ([modelIdentifier isEqualToString:@"iPad4,4"]) return NO;
if ([modelIdentifier isEqualToString:@"iPad4,5"]) return YES;
if ([modelIdentifier isEqualToString:@"i386"]) return NO;
if ([modelIdentifier isEqualToString:@"x86_64"]) return NO;
return YES;
}
(Clearly it could be edited down to remove either the NO or YES only depending on which way you want to err in case there is a new model...)
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