Why this echo construct does not work?
When I do this:
$ /bin/echo 123 | /bin/ec开发者_开发百科ho
I get no o/p. Why is that?
You ask why it doesn't work. In fact, it does work; it does exactly what you told it to do. Apparently that's not what you expected. I think you expected it to print 123
, but you didn't actually say so.
(Note: "stdin" is standard input; "stdout" is standard output.)
/bin/echo 123 | /bin/echo
Here's what happens. The echo
command is executed with the argument 123
. It writes "123", followed by a newline, to its stdout.
stdout is redirected, via the pipe (|
) to the stdin of the second echo
command. Since the echo command ignores its stdin, the output of the first echo is quietly discarded. Since you didn't give the second echo command any arguments, it doesn't print anything. (Actually, /bin/echo with no arguments typically prints a single blank line; did you see that?)
Normally pipes (|
) are used with filters, programs that read from stdin and write to stdout. cat
is probably the simplest filter; it just reads its input and writes it, unchanged, to its output (which means that some-command | cat
can be written as just some-command
).
An example of a non-trivial filter is rev
, which copies stdin to stdout while reversing the characters in each line.
echo 123 | rev
prints
321
rev
is a filter; echo
is not. echo
does print to stdout, so it makes sense to have it on the left side of a pipe, but it doesn't read from stdin, so it doesn't make sense to use it on the right side of a pipe.
"echo" reads from command line, not standard input. So pipeline is not working here.
From bash manual:
echo [-neE] [arg ...]
Output the args, separated by spaces, terminated with a newline.
So your first echo did print "123" to stand output, however, the second echo didn't make use of it so "123" is dropped. Then an empty line is printed as if you run "echo".
You can use cat as Keith Thompson suggested:
echo 123|cat
/bin/echo 123 < /bin/echo
the pipe = concate
http://tldp.org/HOWTO/Bash-Prog-Intro-HOWTO-4.html
Pipes let you use the output of a program as the input of another one
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