开发者

What's wrong with my prepared SQL statement?

I'm new to using PDO and prepared statement so if I'm doing this blatantly wrong please let me know :)

I have the following code:

$stmt = $this->_dbh->prepare( '(SELECT folder_id, "y" AS "has_access", access_type FROM groups_users AS gu LEFT JOIN folders_groups AS fg ON gu.group_id = fg.group_id WHERE user_id = :user_id)
                        UNION
                        (SELECT folder_id, has_access, access_type FROM folders_users WHERE user_id = :user_id AND has_access = :yes)' );
$stmt->bindValue( ':user_id', $this->_user_id, PDO::PARAM_INT );
$stmt->bindValue( ':yes', self::YES, PDO::PARAM_STR );
$stmt->execute();
$folders = $stmt->fetch( PDO::FETCH_ASSOC );

and if I do:

print_r($this->_dbh->errorInfo());                                   
print_r($folders);

$folders is FALSE and my errorInfo() returns:

Array ( [0] => 00000 [1] => [2] => )

Which from my understanding of it means there's no errors. I tried replacing my :user_id and :yes with the values and I don't get errors. The result is empty but my fetch call still returns 开发者_如何学JAVAfalse (which the documentation says that it failed) when I'm expecting an empty array.

Thanks for any help :)


A fetch call which returns false is not an error condition - it just means there's no data to fetch. e.g. your query returned no data. What does $stmt->rowCount() return?

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜