How to select and consume a collection of value objects in an NHibernate QueryOver query
I have a simple model, consisting of a document that references one or more article using a reference object (this is because in the domain, we do not own the articles so we can only reference them).
I'm trying to write a query that lists the documents, printing the ID and a string consisting of a comma separated list of article numbers. For example:
ID ARTICLES
------------------
1 ACC, PE2,
2 ER0, AQ3, FEE
3 PE2
My problem is with selecting the comma separated list.
Here are the domain classes:
// The Entity class has an Id property.
public class Document : Entity
{
public virtual IEnumerable<ArticleReference> ArticleReferences { get; set; }
public virtual DateTime ReceiveDate { get; set; }
}
// The ValueObject does not have an Id property ofcourse.
public class ArticleReference : ValueObject
{
public virtual string ArticleNumber { get; set; }
public virtual string ArticleName { get; set; }
}
The article reference is a value object so it does not have an ID of its own.
This is the view model that represents an item in the result list:
public class DocumentListItemModel
{
public int Id { get; set; }
public string ArticleNumbers { get; set; }
public string ReceiveDate { get; set; }
}
And here's the query class I have come up with so far:
public class DocumentQuery
{
public IList<DocumentListItemModel> ExecuteQuery()
{
IntermediateModel model = null;
ArticleReference articleReferenceAlias = null;
return Session
.QueryOver<Document>()
.JoinAlias(n => n.ArticleReferences, () => articleReferenceAlias);
.SelectSubQuery(
QueryOver.Of<ArticleReference>(() => articleReferenceAlias)
// There is no way of 开发者_开发技巧matching references to documents from a domain
// point of view since the references are value objects and
// therefore don't have an ID.
.Where(n => ...)
.Select(q => articleReferenceAlias.Number))
.WithAlias(() => model.ArticleNumbers)
.TransformUsing(Transformers.AliasToBean<IntermediateModel>());
.Future<IntermediateModel>()
.ToList()
.Select(n =>
new DocumentListItemModel()
{
Id = n.Id,
ArticleNumbers = string.Join(", ", n.ArticleNumbers.OrderBy(p => p)),
ReceiveDate = n.ReceiveDate.ToString("d", CultureInfo.CurrentCulture)
})
.ToList();
}
private class IntermediateModel
{
public int Id { get; set; }
public IEnumerable<string> ArticleNumbers { get; set; }
public DateTime ReceiveDate { get; set; }
}
}
As you can see, I can't express the .Where
statement because there is no way of matching references to documents from a domain point of view. The references are value objects and therefore don't have an ID.
The question is: how do I fix the query to properly select the list of article numbers so I can use it in my string.Join
statement to make the comma separated string?
I think you are taking the definition of value object too literally. Assigning a surrogate identifier (identity column, Guid, etc.) to a value object does not make it any less of a value object. It's a value object because its equality is based its values, not its identity. This does not require that a value object cannot have an identity, and in practice it almost always has to.
Your application obviously has to be able to link a Document to a set of ArticleReferences and the best way to accomplish that is by adding an ID to ArticleReference.
I managed to solve the problem. This is what I ended up with:
public IList<DocumentListItemModel> ExecuteQuery()
{
ArticleReference articleReferenceAlias = null;
return Session
.QueryOver<Document>()
.JoinAlias(n => n.ArticleReferences, () => articleReferenceAlias,
JoinType.LeftOuterJoin)
.SelectList(list => list
.Select(n => n.Id)
.Select(n => articleReferenceAlias.Number))
.List<object[]>()
.Select(x => new
{
Id = (int)x[0],
ArticleNumber = (string)x[1]
})
.GroupBy(n => n.Id).Select(n =>
{
return new DocumentListItemModel
{
Id = n.First().Id,
ArticleNumbers = string.Join(", ", n.Select(p => p.ArticleNumber))
};
}).ToList();
}
}
I couldn't use the alias-to-bean transformer anymore because it cannot handle collection properties. That's why the solution has the GroupBy
, it consolidates the rows, aggregating the article numbers into a string.
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