get a unique brush for numbers
I like to display some decimal numbers. As many as possible need to have a unique brush in WPF.
example
-1.00 (display in Green and Orange)
0.0开发者_如何学运维0 (display in Orange)
1.00 (display in Green)
2.00 (display in Red)
no specified pattern is needed.
RBG is to small for my case.
255 * 255 * 255 = 16 581 375
The color for a value have to be always the same.
public Brush GetValueColor(decimal value)
{
//Generate Brush for value
return myBrush;
}
I don't know what is wrong with my question but whatever. Just need a function to return a unique brush for every unique number. It doesn't mater how the numbers looks like.
You could always generate a LinearGradientBrush
with GradientStops
based on the bytes from value.ToString(). You can also reverse the LinearGradientBrush
back to the decimal value if needed.
GetValueColor
public LinearGradientBrush GetValueColor(decimal value)
{
LinearGradientBrush brush = new LinearGradientBrush();
byte[] byteArray = Encoding.ASCII.GetBytes(value.ToString());
for (int i = 0; i < byteArray.Length; i += 3)
{
byte red = byteArray[i];
byte green = i < byteArray.Length - 1 ? byteArray[i + 1] : (byte)0;
byte blue = i < byteArray.Length - 2 ? byteArray[i + 2] : (byte)0;
brush.GradientStops.Add(
new GradientStop(new Color {A = 255, R = red, G = green, B = blue },
(double)(i+1) / byteArray.Length));
}
return brush;
}
Reverse: GetColorValue
public decimal GetColorValue(LinearGradientBrush brush)
{
List<byte> byteList = new List<byte>();
foreach (GradientStop gradientStop in brush.GradientStops)
{
byteList.Add(gradientStop.Color.R);
byteList.Add(gradientStop.Color.G);
byteList.Add(gradientStop.Color.B);
}
return Convert.ToDecimal(Encoding.ASCII.GetString(byteList.ToArray()));
}
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