Parsing big hexadecimal numbers in Java

I'm trying to开发者_JAVA百科 parse into int a String which is hexadecimal number in my code (FF00FF00, for example) using Integer.parseInt(String string, int radix), but always get NumberFormatException. If I parse the number without last two numbers (FF00FF) it works well.

Is there any method to parse such big numbers in Java?

If Integer is too small, use Long:

Long.parseLong(string, 16)

If Long is still too small, use BigInteger:

new BigInteger(string, 16)

I would use Long.parseLong(x, 16) BigInteger is overkill for a 32-bit value.

If you expect this value to be an int value you can cast the result.

int x = (int) Long.parseLong("FF00FF00", 16);