How to declare looping (for) values as a variable

I wrote a looping function as below :

for($x=0; $x<5; $x++){
     echo "'$x'";
     if($x!=4){
          echo ", ";
     }
}

That will give result

'0', '1', '2', '3', '4'

How can i declare the result as a variable so that i could call and use it. For example, the result above is declared as $values. so that, i only need to call $values to get the '0', '1', '2', '3', '4'. Hope that's开发者_如何学JAVA clear enough to deliver my problem.

You're looking for the range function:

$upToFour = range(0, 4);

Alternatively, you can construct the array in a loop:

$upToFour = array();
for ($i = 0;$i < 5;$i++) {
   $upToFour[] = $i; // Equivalently: array_push($upToFour, $i);
}

If you want to construct the resulting string, use implode:

$upToFourString = implode(',', $upToFour);

, or, if you need the quotes:

$upToFourString = implode(',',
                          array_map(
                            function($num) {return "'" . $num . "'";},
                            $upToFour));

, or, equivalently,

$upToFourString = '';
for($x=0; $x<5; $x++){
     $upToFourString .= "'$x'";
     if($x!=4){
          $upToFourString .= ", ";
     }
}

this will do it with least change in your code

   <?php

        ob_start();
        for($x=0; $x<5; $x++){
             echo "'$x'";
             if($x!=4){
                  echo ", ";
             }
        }
        $values = ob_get_contents();
        ob_end_clean();
        echo $values;

        ?>

$result = array();
for ($x=0; $x<5; $x++)
    $result[] = $x;

Quite simply:

$a = array();
for($x=0; $x<5; $x++){
    array_push($a, $x);
}