php get the number of a given instance in an array

Basically, I'm trying to make a table where the color slightly changes for each row.

I'm going to do this by naming each even row class="even" and every odd row class="odd".

In my loop then, I need to figure out if the instance of the array is odd or even.

I can do almost do this by writing:

if (coun开发者_C百科t($row)%2 == 0)  //while $row is an array from a mysql query
    {
    echo "<tr class='even'>";

if (count($row)%2 == 1)
    {
    echo "<tr class='odd'>";
    }

However writing count($row) gives me the count for the whole array, not the number of the instance which indicates where it falls in the whole array. Any ideas on how I could get the number of the instance within the array?

Thanks

Don't use PHP for this. Use CSS:

tr:nth-child(even) {background: #CCC}
tr:nth-child(odd) {background: #FFF}

Try something like this:

$i = 0;
while ($i < count($row)) {
  if (($i % 2) == 0) {
    echo "<tr class='even'>";
  } else {
    echo "<tr class='odd'>";
  }
  $i++;
}

You could use a counter:

$i = 0   
while($row=mysql_fetch_array($yourquery)) {
   if ($i % 2 == 0) {
      echo "<tr class='even'>";
   } else {
      echo "<tr class='odd'>";
   } 
   $i++;   
}