PHP arrays - display unused vars

Lets say I have

<?php 

$type[ford][focus] = 'some text';
$type[ford][fiesta] = 'some text';

$type[toyota][corola] = 'some text';
$type[toyota][avensis] = 'some text';

$type[bmw][x6] = 'some text';
$type[bmw][x5] = 'some text';

$type[audi][a6] = 'some text';
$type[audi][a8] = 'some text';



function show($car){

foreach ($car as $model)
{
echo $model;
}

}



echo 'Best cars';
show ( $ty开发者_如何学运维pe[bmw] );

echo 'Other cars';
show ( $type[ford] );


?>

What I need is that the rest of cars that are not used (audi and toyota) to be displayed in the last function. So show ( $type[ford] ) should display ford, audi and toyota cars.

Thank you in advance.

I'm making a copy of the original variable here, but you can modify the original too if it's not used anymore after this.

$cars = $type;

echo 'Best cars';
show ( $type[ 'bmw' ] );
unset( $cars[ 'bmw' ] );

echo 'Other cars';
foreach( $cars as $car ) {
    show( $car );
}

I can't see how the items in the array are 'used' as the function isn't in the code but I would recommend using unset() in the function then all that's left in the array is items that are unused.

Also using unset(), but rewriting show() to do the work:

function show($car){
  foreach ($car as $model)
  {
    if(is_array($model)) {
      show($model);
    } else {
      echo $model;
    }
  }
}

$cars = $type;

echo 'Best cars';
show ( $type[ 'bmw' ] );
unset( $cars[ 'bmw' ] );

echo 'Other cars';
show($cars);

This way, you could change $cars to have more levels (for example, the year of the model) and you wouldn't have to change the code.