Can configure and start embedded Tomcat via Spring? OK with Jetty?
Is there a way to configure and setup Embedded Tomcat in Spring? I can do so easily with Jetty 7 that I 开发者_高级运维created a standalone Java application that will start Jetty as webcontainer and finally JUnit test can call the BO via HTTPInvoker.
To me, it seems I have to write code to do so by using Tomcat?
Spring xml file
<!-- Manually start server after setting parent context. (init-method="start") -->
<bean id="jettyServer"
class="org.eclipse.jetty.server.Server"
init-method="start"
destroy-method="stop">
<property name="threadPool">
<bean id="ThreadPool"
class="org.eclipse.jetty.util.thread.ExecutorThreadPool">
<constructor-arg value="0" />
<!--property name="corePoolSize" value="${jetty.server.thread.pool.core.pool.size}"/>
<property name="maximumPoolSize" value="${jetty.server.thread.pool.max.pool.size}"/-->
</bean>
</property>
<property name="connectors">
<list>
<bean id="Connector"
class="org.eclipse.jetty.server.nio.SelectChannelConnector"
p:port="${jetty.server.port}"
p:maxIdleTime="${jetty.server.max.idle.time}"
p:acceptors="${jetty.server.acceptor.num}"
p:confidentialPort="${jetty.server.ssl.port}" />
</list>
</property>
<property name="handler">
<bean class="org.eclipse.jetty.server.handler.HandlerCollection">
<property name="handlers">
<list>
<bean class="org.eclipse.jetty.servlet.ServletContextHandler">
<property name="contextPath" value="/"/>
<property name="sessionHandler">
<bean class="org.eclipse.jetty.server.session.SessionHandler"/>
</property>
<property name="resourceBase" value="."/>
<property name="servletHandler">
<bean class="org.eclipse.jetty.servlet.ServletHandler">
<property name="servlets"> <!-- servlet definition -->
<list>
<!-- default servlet -->
<bean class="org.eclipse.jetty.servlet.ServletHolder">
<property name="name" value="DefaultServlet"/>
<property name="servlet">
<bean class="org.springframework.web.servlet.DispatcherServlet"/>
</property>
<property name="initParameters">
<map>
<entry key="contextConfigLocation" value="classpath:config/DefaultServlet-servlet.xml" />
</map>
</property>
</bean>
</list>
</property>
<property name="servletMappings">
<list><!-- servlet mapping -->
<bean class="org.eclipse.jetty.servlet.ServletMapping">
<property name="pathSpecs">
<list><value>/</value></list>
</property>
<property name="servletName" value="DefaultServlet"/>
</bean>
</list>
</property>
</bean>
</property>
</bean>
<bean class="org.eclipse.jetty.server.handler.RequestLogHandler">
<property name="requestLog">
<bean class="org.eclipse.jetty.server.NCSARequestLog">
<constructor-arg value="${jetty.server.log.dir}/jetty-yyyy_mm_dd.log"/>
<property name="extended" value="false"/>
</bean>
</property>
</bean>
</list>
</property>
</bean>
</property>
</bean>
DefaultServlet-servlet.xml
<!-- This default handler takes care of each of the services enumerated below -->
<bean id="defaultHandlerMapping"
class="org.springframework.web.servlet.handler.BeanNameUrlHandlerMapping" />
<bean id="helloService" class="com.company.ws.bo.HelloServiceImpl"/>
<!-- SpringHTTP Service Exposure -->
<bean name="/HelloService"
class="org.springframework.remoting.httpinvoker.HttpInvokerServiceExporter"
lazy-init="true">
<property name="service" ref="helloService" />
<property name="serviceInterface"
value="com.company.ws.bo.IHelloService" />
</bean>
Tomcat 7 can be used as an embedded Server. As far as I know there is no special spring support, but you don't need special spring support to start an tomcat out of an spring application.
@See: this blog and this (german)
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