what the purpose of position:"last" in jqgrid?

I have question about jqgrid, what the purpose of position:"last" in jqgrid?

for more details, this is my code :

.navButtonAdd("#rowsTransaksi",{
        caption:"",
        buttonicon:"",
        onClickButton:function(){
        var datarow = {acctId: "", currency: "", amount: ""};
        //var su=jQuery("#Transaksi").addRowData(datarow,"last");
        var su=jQuery("#Transaksi").addRowData("X",datarow,"last");
        if(su) { jQuery("#Transaksi").setSelection('X') }
    },  ***position:"last"***

Help me please, tell m开发者_运维百科e about explanation for my question.. =) Thanks.

There are some more important problem in your code. The line addRowData("X",datarow,"last") use always the same "X" value as the rowid, but id must be unique. I suggest you to use $.jgrid.randId() method instead which generate new unique id.

Your code could be rewritten as the following:

var myGrid = $("#Transaksi");
myGrid.jqGrid('navButtonAdd', "#pager", {
    caption: "",
    buttonicon: "ui-icon-plus",
    title: "Add empty row",
    onClickButton: function () {
        var datarow = { acctId: "", currency: "", amount: "" },
            newId = $.jgrid.randId();
        if (myGrid.addRowData(newId, datarow, "last")) {
            myGrid.setSelection(newId);
        }
    },
    position:"first"
});

which will be place the new button which looks like "+" on the first place (before refresh button on the picture below)

see the demo.

From the jqGrid documentation.

position: (“first” or “last”) the position where the button will be added (i.e., before or after the standard buttons).