How to run servlet on tomcat server
I have create following java file,compile it and got .class file.
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class HelloWorld extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws IOException, ServletException
{
resp开发者_开发知识库onse.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<body>");
out.println("<head>");
out.println("<title>First Example</title>");
out.println("</head>");
out.println("<body>");
out.println("<h1>Hello World!</h1>");
out.println("</body>");
out.println("</html>");
}
}
Now i created directory abc/WEB-INF/classes under apache-tomcat-6.0.32/webapps directory so my classFile Path is : apache-tomcat-6.0.32/webapps/abc/WEB-INF/classes/HelloWorld.class and trying to access http://localhost:8080/abc/WEB-INF/classes/HelloWorld, but getting error "The requested resource (/abc/HelloWorld) is not available"
Where i am going wrong? or should i have to specify other configuration?
you must define your servlet in the web.xml
<servlet>
<servlet-name>HelloWorld</servlet-name>
<servlet-class>yourpackage.HelloWorld</servlet-class>
</servlet>
and then define the mapping from URL to servlet
<servlet-mapping>
<servlet-name>HelloWorld</servlet-name>
<url-pattern>/HelloWorld</url-pattern>
</servlet-mapping>
and finally type the URL as:
http://localhost:8080/abc/HelloWorld
You need to configure your servlet in your web.xml.
加载中,请稍侯......
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