Bash Drop Down Menu from contents of Array (CGI-bin/apache2) [duplicate]

This question already has answers here: Closed 11 years ago.

Possible Duplicate:

Output of command in Bash script to Drop-down box?

I have an array in a bash script. I have apache2 configured so I can run cgi/bash scripts in m开发者_高级运维y cgi-bin directory, and they will display like a webpage.

Is there any way to take each element of the array and make it one result in a drop down box on the page?

For example, if my array looked like:

a[0] = "255" 
a[1] = "254" 
a[2] = "253"
a[3] = "252"
a[4] = "251"

I would want the dropbox to look like (lol, ASCII)

 _____
|255  |
|254  |
|253  |
|252  |
|251  |
 -----

Any suggestions? Thanks for your help.

---

you can write a bash for loop to do everything. This just prints out the elements:

for i in `seq 1 "${#x[*]}"`; do
    echo "|${x[i]} |"
done

To get the alignment correct, you need to figure out the max length (one loop) and then print out the terms:

# w will be the length
w=0
for i in `seq 1 "${#x[*]}"`; do
    if [ $w -lt ${#x[$i]} ]; then w=${#x[$i]}; fi
done
for i in `seq 1 $((w+2))`; do printf "%s" "-"; done
printf "\n"
for i in `seq 1 "${#x[*]}"`; do
    printf "|%-$ws |\n" ${#x[$i]}
done
for i in `seq 1 $((w+2))`; do printf "%s" "-"; done
printf "\n"

---

Slightly simpler (but more verbose) solution:

box()
{
    local -a a=(1 20 300 4000 50000)
    local -i w=0

    for i in "${a[@]}"
    do
        [ $w -lt $i ] && w="${#i}"
    done

    printf -- '-%.s' $(seq $w)
    printf -- '---\n'

    for i in "${a[@]}"
    do
        printf -- '|%-'$w's |\n' $i
    done

    printf -- '-%.s' $(seq $w)
    printf -- '---\n'
}