How to pass Virtually Anything To A Function In C++ (or C)?
I need to pass something like a pointer that takes anything as a function parameter. You know, something without any predefined type or a type that can take anything like this:
void MyFunc( *pointer );
And then use it like:
char * x = "YAY!";
MyFunc(x);
in开发者_JAVA百科t y = 10;
MyFunc(&y);
MyObj *b = new MyObj();
MyFunc(b);
And I don't want to use templates because I am mostly using C in my project. Is there anything that can be used here except a function macro?
In C++, Boost.Any will let you do this in a type-safe way:
void func(boost::any const &x)
{
// any_cast a reference and it
// will throw if x is not an int.
int i = any_cast<int>(x);
// any_cast a pointer and it will
// return a null pointer if x is not an int.
int const *p = any_cast<int>(&x);
}
// pass in whatever you want.
func(123);
func("123");
In C, you would use a void pointer:
void func(void const *x)
{
// it's up to you to ensure x points to an int. if
// it's not, it might crash or it might silently appear
// to work. nothing is checked for you!
int i = *(int const*)x;
}
// pass in whatever you want.
int i = 123;
func(&i);
func("123");
You seem adverse to it but I'll recommend it anyway: if you're using C++, embrace it. Don't be afraid of templates. Things like Boost.Any and void pointers have a place in C++, but it is very small.
Update:
Well , I am making a small signals - slots - connections library to be used with my gui toolkit. So that I can get rid of the Ugly WNDPROC. I need these pointers for the connections.
If you need multi-target signals, Boost.Signals already provides a full and tested signals/slots implementation. You can use Boost.Bind (or std::bind
, if you've got a C++0x compiler) to connect member functions:
struct button
{
boost::signal<void(button&)> on_click;
}
struct my_window
{
button b;
my_window()
{
b.on_click.connect(std::bind(&my_window::handle_click,
this, std::placeholders::_1));
}
void handle_click(button &b)
{
}
void simulate_click()
{
b.on_click(b);
}
};
If you only want a simple callback, Boost.Function (or std::function
if you've got a C++0x compiler) will work well:
struct button
{
std::function<void(button&)> on_click;
}
struct my_window
{
button b;
my_window()
{
b.on_click = std::bind(&my_window::handle_click,
this, std::placeholders::_1);
}
void handle_click(button &b)
{
}
void simulate_click()
{
b.on_click(b);
}
};
You can use a function that takes a void*
, but you must be aware of the pointer types that are not compatible with void*
:
pointers to functions:
void MyFunc(void*); MyFunc(&MyFunc); // WRONG
pointers to members:
void MyFunc(void*); struct A { int x; }; MyFunc(&A::x); // WRONG
While these pointers are not compatible with void*
(even with casting, on some compilers), they are themselves data. So you can pass a pointer to the pointer:
void MyFunc(void*);
void (*pfn)(void*) = &MyFunc;
MyFunc(&pfn); // ok
struct A { int x; };
int A::*px = &A::x;
MyFunc(&px); // ok
You can define the method as taking one void *
argument. Of course, at that point, it's up to you to figure out what to do with the data (as far as accessing it or casting it.)
void MyFunc(void * ptr);
You could use:
void MyFunc( void* p){}
int g = 10;
MyFunc( (void*)&g );
void *
is the way to do it. You can assign any pointer type to and from a void *
. But to use the pointer in the called function, you'll have to know the type so you can create an appropriate local pointer or cast appropriately. You can encode a limited set of types as enum symbols, and perhaps use a switch to select type-specific behavior. But without a specific purpose or use-case, you might end up chasing your tail in a quest for generality for which C was never intended.
Another way would be to make a union to contain all the various types you know are needed.
typedef union {
int i;
char c;
float f;
} vartype;
Then if the value can carry around its own type-identifier, it becomes a tag-union or variant-record.
typedef struct {
enum type { INT, CHAR, FLOAT } type;
vartype var;
} varrec;
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