C++ to C#, static_cast into enum

I'm trying to convert a bit of VC 6.0 C++ code to C#. Specifically, I'm parsing through a binary dat file and I've run into a problem converting this bit of code:

ar.GetFile()->Read(buf,sizeof(int));  
memmove(&x,buf,4);

pEBMA->before_after = static_cast<enum EBMA_Reserve>(x);
pEBMA->method       = static_cast<enum EBMA_Method>(x >> 4);

Here is some related code.

struct EBMA_Data *pEBMA = &EBMA_data;

typedef CArray<struct EBMA_Data,struct EBMA_Data&> EBMA_data;

enum EBMA_Reserve
   {EBMA_DONT_RESERVE,
    EBMA_BEFORE,
    EBMA_AFTER
   };

enum EBMA_Method
   {EBMA_CENTER,
    EBMA_ALL_MATERIAL,
    EBMA_FRACTION,
    EBMA_RESERVE
   };


struct EBMA_Data
   {double reserved;
    double fraction;
    enum EBMA_Method method : 4;
    enum EBMA_Reserve before_after : 4;
   };

I've read this thread here Cast int to Enum in C#, but my code isn't giving me the same results as the legacy program.

Here is some of my code in C#:

reserved = reader.ReadDouble();
fraction = reader.ReadDouble();
beforeAfter = (EBMAReserve)Enum.ToObject(typeof(EBMAReserve), x);
method = (EBMAMethod)Enum.ToObject(typeof(EBMAMethod), (x >> 4));

I do ha开发者_Go百科ve an endianness problem so I am reversing the endianness like so.

public override double ReadDouble()
        {
            byte[] b = this.ConvertByteArrayToBigEndian(base.ReadBytes(8));
            double d = BitConverter.ToDouble(b, 0);
            return d;
        }
 private byte[] ConvertByteArrayToBigEndian(byte[] b)
        {
            if (BitConverter.IsLittleEndian)
            {
                Array.Reverse(b);
            }

            return b;
        }

So then I thought that maybe the endianness issue was still throwing me off so here is another attempt:

byte[] test = reader.ReadBytes(8);
Array.Reverse(test);
int test1 = BitConverter.ToInt32(buffer, 0);
int test2 = BitConverter.ToInt32(buffer, 4);
beforeAfter = (EBMAReserve)test1;
method = (EBMAMethod)test2;

I hope I've given enough details about what I'm trying to do.

EDIT:

This is how I solved my issue, apparently the values I needed were stored in the first byte of a 4 byte segment in the binary file. This is in a loop.

byte[] temp = reader.ReadBytes(4);
byte b = temp[0];

res = (EBMAReserve)(b & 0x0f);
meth = (EBMAMethod)(b >> 4);

EDIT: It actually looks like the structure size of EBMA_Data is 17 bytes.

struct EBMA_DATA
{
  double reserved; //(8 bytes)
  double fraction; //(8 bytes)
  enum EBMA_Method method : 4; //(this is packed to 4 bits, not bytes)
  enum EMBA_Reserve before_after : 4; //(this too, is packed to 4 bits)
}

so your read code should look something more like this:

 EBMA_Data data = new EBMA_Data;
 data.reserved = reader.ReadDouble();
 data.fraction = reader.ReadDouble();
 byte b = reader.ReadByte();
 data.method = (EBMAMethod)(b >> 4);
 data.before_after = (EBMAReserve)(b & 0x0f);

Not 100% sure, but it looks like the code that does the shift x >> 4 bytes may be the underlying issue that's being overlooked. If the EBMAReserve is the lower 4 bits of x and EBMAMethod is the top 4 bits, maybe this code would work?

 EBMAReserve res = (EBMAReserve)(x & 0x0f);
 EBMAMethod meth = (EBMAMethod)(x >> 4);

I think that is what the : 4 means after the enumerations in the struct, it's packing the two enums into the structure as a single byte instead of 2 bytes.