SQL query - How to exclude WHERE for specific field
See the SQL query below, it work fine. It calculate the number of Yes, NOT, Other and the number of matching mobile number [Sales field] (D.MobileNo = S.mobile
)
SELECT D.Username,
SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'Not' THEN 1 ELSE 0 END) as Not,
SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other,
SUM(CASE WHEN S.mobile IS NULL THEN 0 ELSE 1 END) as Sales,
COUNT(*) as TOTAL
FROM dairy as D
LEFT JOIN (SELECT DISTINCT mobile FROM sales) as S on D.MobileNo = S.mobile
WHERE source = 'Network'
AND UNIX_TIMESTAMP(CheckDate) >= 1309474800
AND UNI开发者_开发百科X_TIMESTAMP(CheckDate) <= 1311894000
GROUP BY D.Username
ORDER BY TOTAL DESC
I want to exclude WHERE
for the Sales
field - it should not be part from CheckDate
. Meaning it should check any record in the dairy
table without CheckDate
for the Sales
field.
How can that be done?
If you really want those results in only one query, this might do the trick.
SELECT D.Username,
SUM(CASE WHEN D.type = 'Yes' AND UNIX_TIMESTAMP(CheckDate) >= 1309474800 AND UNIX_TIMESTAMP(CheckDate) <= 1311894000 THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'Not' AND UNIX_TIMESTAMP(CheckDate) >= 1309474800 AND UNIX_TIMESTAMP(CheckDate) <= 1311894000 THEN 1 ELSE 0 END) as Not,
SUM(CASE WHEN D.type = '' AND UNIX_TIMESTAMP(CheckDate) >= 1309474800 AND UNIX_TIMESTAMP(CheckDate) <= 1311894000 THEN 1 ELSE 0 END) as Other,
SUM(CASE WHEN S.mobile IS NULL THEN 0 ELSE 1 END) as Sales,
COUNT(*) as TOTAL,
SUM(CASE WHEN UNIX_TIMESTAMP(CheckDate) >= 1309474800 AND UNIX_TIMESTAMP(CheckDate) <= 1311894000 THEN 1 ELSE 0 END) AS TOTALINCHECKDATE
FROM dairy as D
LEFT JOIN (SELECT DISTINCT mobile FROM sales) as S on D.MobileNo = S.mobile
WHERE source = 'Network'
GROUP BY D.Username
ORDER BY TOTAL DESC
Note that "TOTAL" will count all rows (including those who where not within your CheckDate range), TOTALINCHECKDATE return the same value as in your previous query.
Obviously, this can still be optimized.
Assuming username exists also in SALES table
SELECT Username,SUM(Yes) As Yes, SUM(`Not`) As `Not`
, SUM(Other) As Other, SUM(sales) Sales, SUM(total)
FROM (
-- get diary data
SELECT username,mobileNo As mobile,
CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END as Yes,
CASE WHEN D.type = 'Not' THEN 1 ELSE 0 END as `Not`,
CASE WHEN D.type = '' THEN 1 ELSE 0 END as Other,
0 As sales, 1 as total
FROM dairy as D
WHERE source = 'Network'
AND UNIX_TIMESTAMP(CheckDate) >= 1309474800
AND UNIX_TIMESTAMP(CheckDate) <= 1311894000
UNION ALL
-- get all sales
SELECT DISTINCT username,mobile, 0 as Yes, 0 as `Not`, 0 As Other, 1 As sales, 0 As total
FROM sales
WHERE UNIX_TIMESTAMP(CheckDate) >= 1309474800
AND UNIX_TIMESTAMP(CheckDate) <= 1311894000
) AS a
GROUP BY Username
Also try your original query with date addition
SELECT D.Username,
SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'Not' THEN 1 ELSE 0 END) as Not,
SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other,
SUM(CASE WHEN S.mobile IS NULL THEN 0 ELSE 1 END) as Sales,
COUNT(*) as TOTAL
FROM dairy as D
LEFT JOIN (SELECT DISTINCT mobile FROM sales WHERE UNIX_TIMESTAMP(CheckDate) >= 1309474800 AND UNIX_TIMESTAMP(CheckDate) <= 1311894000 ) as S on D.MobileNo = S.mobile
WHERE source = 'Network'
AND UNIX_TIMESTAMP(CheckDate) >= 1309474800
AND UNIX_TIMESTAMP(CheckDate) <= 1311894000
GROUP BY D.Username
ORDER BY TOTAL DESC
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