SQL Query to obtain Trip Details
I have a table which has columns like StartDate
, EndDate
, Registration_No
, Start_Odometer
, End_Odometer
, Stop_time
, Running_Time
, Idle_Time
, Distance
, StartOPID
, EndOPID
..
StartOPID
, EndOPID
can have values like 5 or 1. I consider a trip when StartOPID=5
and EndOPID=5
. A Vehicle can have many trips on the same date but the timings differ. I need to write a query where I can get the Trip details of a particular vehicle during the day which has StartOPID=5
and EndOPID=5
& also I need to get the total distance, stoptime,idletime during this trip..
I have written a query but its not giving me the desired result..plz help..
select
Registration_No,
StartDate,
EndDate,
Start_Odometer,
End_Odome开发者_StackOverflowter,
sum(Total_Trip_Time) as Total_Trip_Time,
sum(Idle_Time) as Idle_Time,
sum(Stop_Time) as Stop_Time,
sum(Running_Time) as Running_Time,
sum(Distance) as Distance
from dbo.Trip_Summary
where System_Id = ?
and Client_Id = ?
and Registration_No = ?
and StartDate between ? and ?
and((StartOPID=5 and EndOPID=1) or (StartOPID=1 and EndOPID=5))
group by StartDate, Registration_No, EndDate, Start_Odometer, End_Odometer
order by StartDate, Registration_No
In my opinion, you might want to remove Start_Odometer and End_Odometer from group by clause. I assume each trip will have different start_odometer and end_odometer. If so, you will not get total trip time etc., per vehicle on a day. You will get total trip time per trip.
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