batch script to set a variable with the current path location

How can I set a variable with the current location? For instance, if I get in c:\test and want to set the variable to test and if I get inside c:\test\test2 the variable will be set to开发者_JAVA百科 test2.

I'm thinking about using a for to get inside a lot of folders and check if some file exists, if the correct file exist I want to set the current folder to a variable so I can copy the path and copy the folder.

The main problem deals with copying the rest of the files is the same folder as the .inf file.

The current directory is in the "shadow" variable cd.
You could try

set "var=%cd%"

%~dp0

This expands into the drive & path of the currently running batch file. I usually surround my batch files with something like:

@echo off
pushd %~dp0

...

popd

Edit: It seems I didn't understand the OP. My example gets the location of the currently running script, not the "Current Directory". +1 to jeb.

I think there is a little confussion here. %CD% always have the current directory, so you don't need to add anything to have it. However, by rereading your original question, I think that you need the LAST PART of the current directory, that is, the name of the current location excluding all previous locations. If so, then you may use this:

set i=0
:nextdir
set /a i+=1
for /f "tokens=%i% delims=\" %%a in ("%CD%") do if not "%%a" == "" set lastdir=%%a& goto nextdir
echo Current location: %lastdir%