POW function and xcode

Working on a specific calculation, got some great help last time! Getting an error now:

Too few arguments to function call, expected 2, have 1

But there are two arguments! The division of twodouble and onedouble will result in one number, the other (1.0/3), being the second argument. Ideas? (Code is below).

-(IBAction)calculate:(id)sender{
    NSString *oneField = self.one.text;
    NSString *twoField = self.two.text;
    double resultInNum;
    double one开发者_运维问答double = [oneField doubleValue];
    double twodouble = [twoField doubleValue];
    resultInNum = pow((twodouble/onedouble),(1.0/3))*.999)*5.005;
    NSString *finalValue = [[NSString alloc] initWithFormat:@"%.3f", resultInNum];
    self.result.text = finalValue;
}

resultInNum = pow((twodouble/onedouble),(1.0/3))*.999)*5.005;

Should be:

resultInNum = pow(twodouble/onedouble, 1.0/3)*0.999*5.005;

Just to let you know: pow is a C function and doesn't use a messaging system like Obj-C methods. My gut instinct is telling me you might be thinking like that.

You have too many parentheses. Look carefully. You're only passing one argument to the pow function.

resultInNum = ((pow(twodouble/onedouble),(1.0/3));

should be

resultInNum = pow((twodouble/onedouble),(1.0/3));

EDIT: It looks like you updated your code after I posted my answer. You're still messing up the parentheses.

pow((twodouble/onedouble),(1.0/3))*.999)*5.005;

should be:

pow((twodouble/onedouble),(1.0/3))*.999*5.005;