Mysql Select Code Doesn't work
I have my php/mysql SELECT code which doesn't return a result to what I have expected after execution of the code. Code: [Select]
$sql="SELECT *FROM advert
WHERE ad_Type = '%{$service}%' AND
开发者_如何学Python ad_Street_No like '%{$location}%' OR
ad_Street_Name like '%{$location}%' OR
ad_Suburb like '%{$location}%' OR
ad_Postcode like '%{$location}%' OR
ad_State like '%{$location}%'";
The user will search on location and the type of service available using parameters like street name,suburb, postcode and/or state in one textfield and then select a type of service from a dropdown menu. So for example : "Select records from table 'advert' where type of service = 'e.g. hauling,digging,' located at e.g. Cardiff NSW". " something like that.
I have 2 records right now on my database : 1. Service: Hauling, Location: Cardiff NSW 2. Service: Digging , Location: Cardiff NSW
Now the problem is:
you search for "Hauling" service in "Cardiff" , will return 2 records (#1 and #2). you search for "Digging" service in "Cardiff", will return 2 records (#1 and #2). you search for either of the services in " Cardiff NSW", will return 0 results.
I got no idea on how to fix this. Please help me guys. Thank you in advance. :( :( :(
Best regards
First off, you need some brackets:
$sql="SELECT *FROM advert
WHERE ad_Type like '%{$service}%' AND
( ad_Street_No like '%{$location}%' OR
ad_Street_Name like '%{$location}%' OR
ad_Suburb like '%{$location}%' OR
ad_Postcode like '%{$location}%' OR
ad_State like '%{$location}%'" );
That will fix your first case. But you also need to think about exactly what it is you're providing : for instance if you only provide a town then you don't want to include ad_Type in your query at all.
$sql = "SELECT * FROM advert
WHERE ad_Type like '%{$service}%'
AND (
ad_Street_No like '%{$location}%'
OR
ad_Street_Name like '%{$location}%'
OR
ad_Suburb like '%{$location}%'
OR
ad_Postcode like '%{$location}%'
OR
ad_State like '%{$location}%'
)";
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